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Nataly [62]
4 years ago
11

How close is the nearest star in miles?

Physics
1 answer:
Tamiku [17]4 years ago
7 0
No one knows yet, but Alpha Centauri is an obvious target. It's the nearest star system to our sun at 4.3 light-years away. That's about 25 trillion miles (40 trillion km) away from Eart
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An object moves along the grid through the points A, B, C, D, E, and Fas shown below.
sveticcg [70]

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.

7 0
3 years ago
The scientist who suggested that atoms contain a hard core containing most of the mass of an atom was:
stich3 [128]
The scientist who suggested that atoms contain a hard core containing most of the mass of an atom was Ernest Rutherford.
5 0
3 years ago
Which system sends nutrients to all the body's cells? excretory system nervous system circulatory system endocrine system
olga55 [171]

The circulatory system sends nutrients to the body's cells.

4 0
3 years ago
Read 2 more answers
A ball rolls from point A to point B. The total energy of the ball at point A isn’t the same as the sum of its potential energy
rusak2 [61]

Answer:

option b

Explanation:

because the law of conservation

it means that energy can never created nor be destroyed

even it will change into another form if energy

7 0
3 years ago
A camera lens used for taking close-up photographs has a focal length of 22.0 mm. The farthest it can be placed from the film is
Arada [10]

Answer:

p = 6.64 cm

Explanation:

For this exercise we use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image, respectively

They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image

          \frac{1}{p} = \frac{1}{f} - \frac{1}{q}

          1 / p = 1 / 2.2 - 1/3.29

           1 / p = 0.15059

           p = 6.64 cm

therefore the farthest distance from the object is 6.64 c

3 0
3 years ago
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