As it is outside the focal point it must be real.Real images must be inverted.
As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size.
Hope this helps you :)
Answer:
a) Fi = 85.76 N
b) Fi = 87.8 N
Explanation:
Given:-
- Density of hydraulic oil, ρ = 804 kg/m^3
- The radius of input piston, ri = 0.00861 m
- The radius of output piston, ro = 0.141 m
Find:-
What input force F is needed to support the 23000-N combined weight of a car and the output plunger, when
(a) the bottom surfaces of the piston and plunger are at the same level
(b) the bottom surface of the output plunger is 1.10 m above that of the input plunger?
Solution:-
For part a.
- We see that both plungers are equal levels or there is no pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers to be equal. This part is an application of Pascal's Law:
Pi = Po
Fi / Ai = Fo / Ao
Fi = Ai / Ao * Fo
Fi = (ri/ro)^2 * Fo
Fi = ( 0.00861 / 0.141 )^2 * 23000
Fi = 85.76 N
For part b.
- We see that both plungers are at different levels so there is pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers plus the differential in heads. This part is an application of Bernoulli's Equation:
Pi = Po + ρ*g*h
Where, h = Elevation head = 1.10m
Fi = (ri/ro)^2 * Fo + ρ*g*h*π*ri^2
Fi = 85.76 + (804*9.81*1.1*3.142*0.00861^2)
Fi = 87.8 N
Answer:
The mass is inversely proportional to the acceleration so the acceleration a1 is twice that acceleration a2

Explanation:
The force of friction and the kinetic force make the law of mass in moving so





The forces are the same however at the moment to determinate the acceleration


are constant because they make the same motion however the difference of mass make the acceleration difference
A) The rhino's average velocity on the x-axis is

. The position x after time t=21.5 s can be found by using the relationship:

where we used

as the x-position at time t=0, since the rhino was at the origin.
SImilarly, the average velocity on the y-axis is

, and the y-position after time t=21.5 s can be found by using:

where we used

since the the rhino was at the origin at time t=0.
b) The distance of the rhino from the origin can be calculated by calculating the resultant of the displacement of the rhino on both axes: