Answer:
The current lags the potential difference by π/2 in an inductor
Explanation:
The potential difference leads to the current by . Alternate signals such as current and voltage -in this case- are periodic, this means that this signals are repeated at fixed spaces of time. Thus, In an inductor the current lags the potential difference by .
60 RPM equals one hertz (i.e., one revolution per second, or a period of one second). The SI unit for period is the second.
Answer:
P = 5sin(880πt)
Explanation:
We write the pressure in the form P = Asin2πft where A = amplitude of pressure, f = frequency of vibration and t = time.
Now, striking the middle-A tuning fork with a force that produces a maximum pressure of 5 pascals implies A = 5 Pa.
Also, the frequency of vibration is 440 hertz. So, f = 440Hz
Thus, P = Asin2πft
P = 5sin2π(440)t
P = 5sin(880πt)
To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:
Mass of copper wire
Density
Resistively of copper
Resistance (R) = 0.390\Omega
Volume is defined as,
(1)
We know that,
(2)
Multiplying equation we have
Therefore the length of the wire is 1.68m
The coin would probably slowly slide down whichever end it is closer to, weigh down the end of the paper, and fall off. It kinda depends on how you hold the paper though, because if it is directly in middle, and you hold it on both ends, it will stay on the paper.