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1 year ago

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The summit of Mount Everest is 8848.0 m above sea level, making it the highest summit on Earth. In 1953, Edmund Hillary was the

first person to reach the summit. Suppose upon reaching there, Hillary slid a rock with a 45.0 g mass down the side of the mountain. If the rock’s speed was 27.0 m/s when it was 8806.0 m above sea level, how much work was done on the rock by air resistance?

1 answer:

Aleksandr-060686 [28]1 year ago

6 0

The work done on the rock by air resistance is 39019.68 J

<h3>Data obtained from the question </h3>

Mass (m) = 45 g
Velocity (v) = 27 m/s
Height (h) = 8848 m
Work done =?

<h3>Definition of work </h3>

Work is simply defined as the product of force and distance moved in the direction of the force.

Work = Force × distance

From the question given above, we can see that height is involved. Thus,

Work = potential energy

Potential energy = mass (m) × acceleration due to gravity (g) × height (h)

Potential energy = mgh

Therefore,

Work = mgh

With the above formula, we can obtain the work done.

<h3>How to determine the work done </h3>

Mass (m) = 45 g = 45 / 1000 = 0.45 Kg
Height (h) = 8848 m
Acceleration due to gravity (g) = 9.8 m/s²
Work done =?

Work = mgh

Work = 0.45 × 9.8 × 8848

Work = 39019.68 J

Learn more about workdone:

brainly.com/question/17358222

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A person who weighs 800N on the earth's surface will weigh 200N at what height above the earth

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Answer: 6,400 km

Explanation:

The weight of a person is given by:

$W=mg$

where m is the mass of the person and g is the acceleration due to gravity. While the mass does not depend on the height above the surface, the value of g does, following the formula:

$g=\frac{GM}{r^2}$

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r is the distance of the person from the Earth's center

The problem says that the person weighs 800 N at the Earth's surface, so when r=R (Earth's radius):

$800 N= W=mg=m \frac{GM}{R^2}$ (1)

Now we want to find the height h above the surface at which the weight of the man is 200 N:

$200 N = W' = mg' = m \frac{GM}{(R+h)^2}$ (2)

If we divide eq.(1) by eq.(2), we get

$\frac{800 N}{200 N}=\frac{W}{W'}=\frac{(R+h)^2}{R^2}$

$4=\frac{(R+h)^2}{R^2}$

By solving the equation, we find:

$4R^2 = (R+h)^2=R^2+2Rh+h^2\\h^2 +2Rh-3R^2 =0$

which has two solutions:

$h=-3R$ --> negative solution, we can ignore it

$h=R$ --> this is our solution

Since the Earth's radius is $R=6.4\cdot 10^6 m$ , the person should be at $h=R=6.4\cdot 10^6 m=6400 km$ above Earth's surface.

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