Ask question

Ask question

All categories

2 years ago

8

The summit of Mount Everest is 8848.0 m above sea level, making it the highest summit on Earth. In 1953, Edmund Hillary was the

first person to reach the summit. Suppose upon reaching there, Hillary slid a rock with a 45.0 g mass down the side of the mountain. If the rock’s speed was 27.0 m/s when it was 8806.0 m above sea level, how much work was done on the rock by air resistance?

1 answer:

Aleksandr-060686 [28]2 years ago

6 0

The work done on the rock by air resistance is 39019.68 J

<h3>Data obtained from the question </h3>

Mass (m) = 45 g
Velocity (v) = 27 m/s
Height (h) = 8848 m
Work done =?

<h3>Definition of work </h3>

Work is simply defined as the product of force and distance moved in the direction of the force.

Work = Force × distance

From the question given above, we can see that height is involved. Thus,

Work = potential energy

Potential energy = mass (m) × acceleration due to gravity (g) × height (h)

Potential energy = mgh

Therefore,

Work = mgh

With the above formula, we can obtain the work done.

<h3>How to determine the work done </h3>

Mass (m) = 45 g = 45 / 1000 = 0.45 Kg
Height (h) = 8848 m
Acceleration due to gravity (g) = 9.8 m/s²
Work done =?

Work = mgh

Work = 0.45 × 9.8 × 8848

Work = 39019.68 J

Learn more about workdone:

brainly.com/question/17358222

You might be interested in

Mass of water= 357g density water= 1.0g/cm3

aliya0001 [1]

$m=357g\\\\\rho=1.0\ \dfrac{g}{cm^3}\\\\\rho=\dfrac{m}{V}\to V=\dfrac{m}{\rho}\\\\\text{substitute}\\\\V=\dfrac{357g}{1.0\frac{g}{cm^3}}=375g\cdot1.0\dfrac{cm^3}{g}=375\ cm^3$

8 0

3 years ago

A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms

zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift = 10m

Mass = 22kg

Unknown:

Work done by the machine = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

Work done = Force x distance

Here;

Work done = mass x acceleration due to gravity x height

Work done = 22 x 9.8 x 10 = 2156J

5 0

3 years ago

A wave has a wavelength of 4.9 m and a velocity of 9.8 m/s. The medium through which this wave is traveling is then heated so th

garri49 [273]

Answer:

the wavelength is 9.8 meters

Explanation:

We can use the relationship:

Velocity = wavelenght*frequency.

Initially we have:

wavelenght = 4.9m

velocity = 9.8m/s

then:

9.8m/s = 4.9m*f

f = 9.8m/s/4.9m = 2*1/s

now, if the velocity is doubled and the frequency remains the same, we have:

2*9.8m/s = wavelenght*2*1/s

wavelenght = (2*9.8m/s)*(1/2)s = 9.8 m

6 0

3 years ago

Read 2 more answers

A 25-kg wagon has a momentum of 300kg m/s. What is it’s acceleration?

arsen [322]

The answer is 12 ....

8 0

3 years ago

An archer fires an arrow at a castle 230 m away. The arrow is in flight for 6 seconds, then hits the wall of the castle and stic

Vika [28.1K]

Answer:

(a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

Explanation:

Given that,

Horizontal distance = 230 m

Time t = 6 sec

Vertical distance = 16 m

We need to calculate the horizontal component

Using formula of horizontal component

$R =u\cos\theta t$

Put the value into the formula

$\dfrac{230}{6} = u\cos\theta$

$u\cos\theta=38.33$ .....(I)

We need to calculate the height

Using vertical component

$H=u\sin\theta t-\dfrac{1}{2}gt^2$

Put the value in the equation

$16 =u\sin\theta\times6-\dfrac{1}{2}\times9.8\times6^2$

$u\sin\theta=\dfrac{16+9.8\times18}{6}$

$u\sin\theta=32.06$ .....(II)

Dividing equation (II) and (I)

$\dfrac{u\sin\theta}{u\cos\theta}=\dfrac{32.06}{38.33}$

$\tan\theta=0.8364$

$\theta=\tan^{-1}0.8364$

$\theta=39.90^{\circ}$

(a). We need to calculate the initial speed

Using equation (I)

$u\cos\theta\times t=38.33$

Put the value into the formula

$u =\dfrac{230}{6\times\cos39.90}$

$u=49.96\ m/s$

(b). We have already calculate the angle.

Hence, (a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

5 0

3 years ago