Answer:
(d) 112 m²
Step-by-step explanation:
The area of a parallelogram is given by the formla ...
A = bh . . . . . . where b is the base length and h is the height
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Here, the base is divided into parts, but their total length is 5m+9m = 14m. The height is given as 8m, so the area is ...
A = (14 m)(8 m) = 112 m²
The area of the parallelogram is 112 square meters.
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<em>Alternate solution</em>
You can also figure this as the sum of the areas of the two triangles and that of the center rectangle.
A = 2(1/2bh) +bh
A = 2(1/2(5 m)(8 m)) +(9 m)(8 m) = 40 m² +72 m² = 112 m²
Here you have to find which each variable is, for this you start of picking one equation,
x + 2y + 6z = 4
-3x + 2y - 2 = -4
4x + 2z = 16
depending the equation you pick you multiply that by a certain number that will give you the opposite of one of the other equations,
-1(x + 2y + 6z = 4)
= -x -2y - 6z = -4
With this you add or subtract it with the equation that has the same number or variable, or both,
In this case it will be the equation,
-3x + 2y + 6z = 4
You can use this one or the third equation since both have a positive 2y which will cancel with -2y from the new equation,
-x - 2y - 6z = -4
-3x + 2y -z = -4
= -4x -7z = -8
Now you since you just eliminated the variable (y) you now have 2 variables, and the last equation has only 2 variables, meaning now you find the answer to those to equations,
-4x -7z = -8
4x + 2z = 16
= -5z = 8
Now leave the variable by itself,
z = 8/5
Now you found the variable (z), with this just substitute on one of the equations we used to find (z) so you can find (x), after that substitute those answered to on of the original equations so you can find (y)
9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
4 bouquets
Step-by-step explanation:
5/5 = 20 flower bouquets.
Find out how much flower bouquets there are when it's 1/5.
5/5 = 20
1/5 = 20 ÷ 5 = 4
Since tulips are 1/5 as 5/5 - 4/5 = 1/5, 4 bouquets are tulips.
Answer:
113.04 cm
Step-by-step explanation:
We know the formula to find the area of a circle is
And we are told to use 3.14 instead of pi so what we have now is,
We are also told the radius, r, is 6. So our equation now looks like this,
is the same as 36, because 6x6 is 36.
Now we have,
Which equals 113.04 and that is the area!
Hope that helps and have a great day!
