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Lubov Fominskaja [6]
3 years ago
5

Solve this quadratic equations: 10k^2-9k+2=0. \large k= \large k=

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0
Solve the equation for k by finding a, b, and c of the quadratic then applying the quadratic formula.
Answer =
K= 1/2 , 2/5
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Solve the system of equations by using substitution . y=2x+13 ,x-y=4
tatyana61 [14]
Step: Solvey=2x+13for y:

y=2x+13


Step: Substitute2x+13foryinx−y=4:

x−y=4

x−(2x+13)=4

−x−13=4(Simplify both sides of the equation)

−x−13+13=4+13(Add 13 to both sides)

−x=17

−x−1=17−1(Divide both sides by -1)

x=−17


Step: Substitute−17forxiny=2x+13:

y=2x+13

y=(2)(−17)+13

y=−21(Simplify both sides of the equation)

D (Bottom Circle)
(-17,-21)



7 0
3 years ago
Identify the values of x and y that make the equation 2x + 5i = 16 + (2y)i true. HELP ASAP!!
aliya0001 [1]

Answer:

x = 8; y = 2.5.

Step-by-step explanation:

As we know , when two complex numbers are equal their real as well as imaginary part are equal.

So comparing on both sides ,

2x = 16   and    5 = 2y

x = 8       and    y = 2.5.

So ,   x = 8; y = 2.5.

5 0
4 years ago
Simplify <br> Rewrite the expression in the form 4n (4^11)(4^-8)
VARVARA [1.3K]

Answer:

k12

Step-by-step explanation:

6 0
2 years ago
Is the green one the correct one?
AleksAgata [21]

Answer:

Yes I think

Step-by-step explanation:

6 0
3 years ago
What is the solution to the following equation?<br> (5x-2)^2=10
GaryK [48]
Take the square root of both sides to get rid of parenthasees, remember to get the positive and negative root
5x-2=+/-√10
add 2 to both sides
5x=2+/-√10
divide by 5
x=\frac{2+/- \sqrt{10} }{y}

x= \frac{2+ \sqrt{10} }{y} or \frac{2- \sqrt{10} }{y}

aprox
x=1.03246 or -0.232456
7 0
3 years ago
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