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3 years ago

Volume ....................

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

360 cm^2

Step-by-step explanation:

length x width x height

6 x 6 x 10

muminat3 years ago

3 0

Answer:

360cm^3

Step-by-step explanation:

V=L*W*H

V=6*6*10

V=36*10

V=360

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7. A rectangular lot is entirely enclosed by a fence.

klasskru [66]

Answer:

it is 390

Step-by-step explanation:

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3 years ago

Please help with the problem in the image!<br> (Dont answer if you don't know it)

Snowcat [4.5K]

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3 years ago

Please help!! markup and markdown word problem.

12345 [234]

Step-by-step explanation:

"markup" contains "up". so, the price goes "up". this is actually increasing the price (e.g. by calculating the profit margin of selling an item on top of the cost of buying the item from the manufacturer).

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3 0

3 years ago

Divide 6k2-15-5 by 3k

TEA [102]

Based on the question above, I believe that '6k2' would be $(6k^2)$ . So by this, I would continue to with the following expression as: $6k^2-15-5\div3k$

$Simplify: \frac{5}{3} \\ \\ ((6 * (k2)) - 15) - ( \frac{5}{3} *k) \\ \\ ((2*3k^2) - 15) - \frac{5k}{3} \\ \\ \boxed{\boxed{6k^2 - 15 = \frac{6k^2-15}{1} = \frac{(6k^2-15)*3}{3} }} \\ \\ (pull \ out \ like \ terms) \\ \\ 6k^2 - 15 = 3 * (2k^2 - 5) \\ \\ Factoring: 2k^2 - 5$

And by this, in order for us to fully understand that this would be true, the following would enable us to understand.

$\Rightarrow \left[\begin{array}{ccc}A+B) * (A-B) =\\
 A2 - AB + BA - B2 =\\
 A2 - AB + AB - B2 = \\
 A2 - B2\end{array}\right] \Leftarrow$

$\boxed{\bf{ \frac{3*(2k^2-5)*3-(5k)}{3} = \frac{18k^2-5k-45}{3} }}$

$Factoring : 18k^2 - 5k - 45 \\ \\ \left[\begin{array}{ccc} -810 + 1 = -809 \\
 -405 + 2 = -403 \\
 -270 + 3 = -267\\ -162 + 5 = -157 \\
 -135 + 6 = -129 \\
 -90 + 9 = -81 
 
 
\end{array}\right]$

$(Your \ Answer) : \boxed{\boxed{\bf{ \frac{18k^2-5k-45}{3} }}}$

4 0

4 years ago

(6^-2·6^5)^-3 can't figure out the answer

deff fn [24]

The answer is 0.000000099.

Hope this helps! :D

6 0

4 years ago