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n200080 [17]
3 years ago
8

1.88 x 10^6/ 2000 ANSWER IN SCIENTIFIC NOTATION

Mathematics
1 answer:
Otrada [13]3 years ago
7 0
Scientific Notation:
2.01445629 • 10^0
Expanded Form:
2.01445629
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Round 1.983 to the nearest hundredth
svet-max [94.6K]

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1.98

Step-by-step explanation:

Find the number in the hundredth place 8 and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

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What is the value of StartFraction 1.6 times 10 Superscript 14 Baseline Over 3.2 times 10 Superscript 7 Baseline EndFraction in
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What point satisfies the inequality y < -4x + 3 and idicates what side should be shaded on a graph.
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4 years ago
Men’s heights are normally distributed with mean 69.5 inches and a standard deviation of 2.4 inches.
Basile [38]

Answer:

a. The percentage of adult men that will fit through the door without bending is 0.

b.  The percentage of adult women that will fit through the door without bending is 0.

c. No, it is not adequate. There must be another technical reasons to not use a larger door.

d. The doorway height that would allow 60% of men to fit without bending is 70.1 inches.

Step-by-step explanation:

a. To fit throught the door, the height has to be under 51.6. To calculate this proportion, we have to calculate the z-score for X=51.6 for the distribution of men's height N(μ=69.5, σ=2.4).

We can calculate the z-score as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{51.6-69.5}{2.4}=\dfrac{-17.9}{2.4}=-7.4583

P(X

The percentage of adult men that will fit through the door without bending is 0.

b. To fit throught the door, the height has to be under 51.6. To calculate this proportion, we have to calculate the z-score for X=51.6 for the distribution of women's height N(μ=63.8, σ=2.6).

We can calculate the z-score as:

z=\dfrac{X-\mu}{\sigma}=\dfrac{51.6-63.8}{2.6}=\dfrac{-12.2}{2.6}=-4.6923

P(X

The percentage of adult women that will fit through the door without bending is 0.

c. No, it is not adequate. There must be another technical reasons to not use a larger door.

d. We can calculate this finding a z-value z1 for which P(z<z1)=0.60.

Looking in a standard normal distribution table, the value for z1 is z1=0.25335.

Then, transforming to our adult men's height distribution, we have:

X=\mu+z\sigma=69.5+0.25335*2.4=69.5+0.6=70.1

The doorway height that would allow 60% of men to fit without bending is 70.1 inches.

5 0
3 years ago
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