Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
Answer:
Step-by-step explanation:
Let's start off with the first equation
5x + y = 60
We need to find what X and Y are.
Let's try subtracting a few numbers from 60.
Let's do 60 - 55 = 5
11x5 = 55
11 = Children Ticket Cost
5 = Seniors Ticket Cost
Without them being the same price!
So using the numbers we found, we can now solve the second one
14x5 = 70
11x11 = 121
70 + 121 = 191
There we go!
Hope this helped! Please give brainiest if you can :)
Answer:
Step-by-step explanation:
A delivery of 4 boxes will contain 2 more defective lightbulbs than a delivery of 2 boxes.
