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astra-53 [7]
3 years ago
5

The following polynomial has factors (x + 8) and (3x + 2). Determine the value of k. −6x^3-55x^2+kx−16

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer:

<h2>k = - 58</h2>

Step-by-step explanation:

Since (x + 8) and (3x + 2) are factors of the polynomial it means that if either one of them is equated to zero and substituted into the polynomial will give us zero

Using x + 8

We have

x + 8 = 0

x = - 8

Substitute the value of x into the polynomial

- 6x³ - 55x² + kx - 16

That's

- 6(-8)³ - 55(-8)² + k(-8) - 16 = 0

-6(-512) - 55(64) - 8k - 16 = 0

Expand

3072 - 3520 - 8k - 16 = 0

Simplify

- 464 - 8k = 0

8k = -464

Divide both sides by 8

k = - 58

Hope this helps you

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IRINA_888 [86]
<h2>'(x+4)^2-1' in the form of (x+a)^2 - b.</h2>

Step-by-step explanation:

We have,

x^2 + 8x + 15

To express x^2 + 8x + 15 in the form of  (x+a)^2 - b = ?

∴ x^2 + 8x + 15

Adding and subtracting 1, we get

= x^2 + 8x + 15 + 1 - 1

= x^2 + 8x + 16 - 1

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Using the algebraic identity,

(x+y)^{2}=x^{2} +2xy+y^{2}

= (x+4)^2-1

Thus, (x+4)^2-1 in the form of (x+a)^2 - b.

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