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wlad13 [49]
3 years ago
15

Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:


..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation:  , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
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mixer [17]

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313

Step-by-step explanation:

First of all you need to find out the surface of the front.

So you need to do 29cm + 29cm = 58cm.

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Next, you need to find the surface of the side.

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After that, you need to find the back surface.

So you need to add 22cm +22cm = 44cm

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Then, you need to do the bottom of the shape.

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2 years ago
Recursive &amp; Explicit Definitions
natali 33 [55]

Answer:

T_{15} = 9565938

Step-by-step explanation:

Given

Sequence: 2, 6, 18, 54, 162,

Required

Determine the 15th term

The above sequence is a geometric sequence. So, first, we calculate the common ratio (r)

r = \frac{T_2}{T_1}

r = \frac{6}{2}

r = 3

The 15th term is calculated as thus:

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T_{15} = 9565938

<em>The 15th term is 9,565,938</em>

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Free_Kalibri [48]

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