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Taya2010 [7]
3 years ago
6

How do you solve Y=x+1 x+2y=14 in substitution?

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

(4, 5 )

Step-by-step explanation:

Given the 2 equations

y = x + 1 → (1)

x + 2y = 14 → (2)

Substitute y = x + 1 into (2)

x + 2(x + 1) = 14 ← distribute and simplify left side

x + 2x + 2 = 14

3x + 2 = 14 ( subtract 2 from both sides )

3x = 12 ( divide both sides by 3 )

x = 4

Substitute x = 4 into (1) for corresponding value of y

y = 4 + 1 = 5

Solution is (4, 5 )

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What’s the an and the a10
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Answer:

an = -6 + n

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Step-by-step explanation:

an should start at one behind the first number so it should be -6. Then we add  whatever the sequence is increasing by, which is 1 in this case, multiplied by n.

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Find the solutions of the system y = –2x – 1 and y = 3–x–1.
sweet [91]

There are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a^x

where a is a constant and a>1

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two equations:

y = –2x – 1 and

\rm y = 3^{-x-1}

From the graph, we can see:

There are two intersection points:

(-1, 1) and (-2, 3)

The x coordinates are -1 and -2

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Thus, there are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

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