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vlabodo [156]
4 years ago
13

Which graph represents g(x)=(x−3)2−5 ?

Mathematics
2 answers:
faltersainse [42]4 years ago
8 0
The graph has vertex (3, -5),
and it is looking upward because it is positive coefficient in front of (x-3)²
Correct answer is A.
777dan777 [17]4 years ago
4 0
The one on the top right
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Need the answer ASAP
Tanzania [10]

Answer:

You would need about 290 blocks, and the scale factor would be 1450:290.

Step-by-step explanation:

     5ft: 1 block

1450ft: x blocks

So,

1450 x 1 = 1450 ÷ 5 = 290

And now we have,

     5ft: 1 block

1450ft: 290 blocks

Hope this helps. Have an amazing day!

8 0
3 years ago
Write a quadratic function whose graph has a vertex of $\left(3,2\right)$ and passes through the point $\left(4,7\right)$ . $f\l
forsale [732]

Answer: Write a quadratic function in vertex form whose graph has the vertex (1,2) and passes through the point (3,10). (what does F(x)=?) Algebra -> Quadratic Equations and Parabolas -> SOLUTION: Write a quadratic function in vertex form whose graph has the vertex (1,2) and passes through the point (3,10).

Step-by-step explanation:

8 0
4 years ago
What is the area of the parallelogram shown below
CaHeK987 [17]

Answer:

please add an image my bro

Step-by-step explanation:

we cant answer without knowing what it looks like

7 0
3 years ago
Read 2 more answers
Write the standard form of an equation with p=3 sqrt2, theta= 135°​
Arlecino [84]

Answer:

x - y + 6 = 0

Step-by-step explanation:

In normal form of a straight line, the equation is given by  

x\cos \theta + y\sin \theta = p

where p is the perpendicular distance of the line from the origin and \theta is the angle between the perpendicular line and the positive direction of the x-axis.

Here, in our case p = 3\sqrt{2} and \theta = 135 Degree,

Therefore, the normal form of the straight line equation is  

x \cos 135 + y \sin 135 = 3\sqrt{2}

⇒ x \cos (180 - 45) + y \sin (180 - 45) = 3\sqrt{2}

⇒ - x \cos 45 + y \sin 45 = 3\sqrt{2} {Since, Cos (180 - Ф) = - Cos Ф and Sin (180 - Ф) = Sin Ф}

⇒- \frac{x}{\sqrt{2}} + \frac{y}{\sqrt{2}} = 3\sqrt{2}

⇒ - x + y = 3√2 × √2 = 6

⇒ x - y + 6 = 0  

So, the standard form of the equation is x - y + 6 = 0. (Answer)

7 0
4 years ago
What are the x and y intecepts of the graph of the equation 6x - 5y=3
otez555 [7]
The y-intercept is negative 3/5. 

The x-intercept is negative 1/2

this is because i plugged in 0 for x, and got the y-intercept and plugged in 0 for y and got the x-intercept
6 0
3 years ago
Read 2 more answers
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