Question

The area of the rectangle shown is at most of 140 square cm

Answer 1

x would be equal to or less than 4. It would not be possible for it to have a length of 15 because 15x10=150 and the maximum area is 140 sq cm.

Answer 2

Answer:

Step-by-step explanation:

Part A:

The length is given as = $3x+2$ cm

The width is give as = 10 cm

Area of rectangle = length x width

Area = $(3x+2)10$

Given is that the area of the rectangle shown is at most of 140 square cm.

So, we can write this as:

$(3x+2)10 \leq140$

Solving this we get;

$30x+20 \leq140$

=> $30x \leq140-20$

=> $30x \leq120$

We get $x \leq4$

So, $3(4)+2$ = 14 cm

Hence, the length can be 14 cm and width is 10 cm.

Part B:

No, it is not possible as if the length will be 15, it will give an area of 150 cm square that is greater than 140 cm square.