Consider the equation:
Subtracting '4' from both the sides of the equation, we get as
Squaring on both the sides of the equation, we get
Subtracting '2' from both the sides of the equation, we get
x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
Answer:
A. 12
Step-by-step explanation:
Recall: one of the properties of a parallelogram is that the diagonals bisect each other. This means that:
LJ = 2(LW)
11x + 2 = 2(5x + 2)
11x + 2 = 10x + 4
11x + 2 - 2 = 10x + 4 - 2
11x = 10x + 2
11x - 10x = 10x + 2 - 10x
x = 2
✅LW = 5x + 2
Plug in the value of x
LW = 5(2) + 2
LW = 10 + 2 = 12
I think is A or b go try it am not 100% sure
Answer:
I'm pretty sure the answer is 34.5
Step-by-step explanation:
the small triangle on the left area is 1.5
the rectangle formed area is 18
the triangle on top area is 9
I believe the triangle's area on the right is 6
