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Leni [432]
3 years ago
14

Mrs. Warren had 1/2 of a cherry pie left over. She split the leftover pie evenly between her 4

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0
Answer = 4/8

1/2 divided by 4
1/2 • 4 (reciprocal)
1/2 • 4/1
4/8
MAVERICK [17]3 years ago
6 0

Answer:

\frac{1}{8}

Step-by-step explanation:

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Find the value of y...​
soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

33^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1

Calculate:

(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1

Solve using substitution:

(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1     t=3^{y}

Solve the equation for t:

t^{2}*\frac{1}{3}+\frac{2}{3}t=1

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

3^{y}=1

y=0

5 0
2 years ago
According to the U.S. Bureau of the Census in its Current Population Reports (Series P60) the average
Dahasolnce [82]

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Step-by-step explanation:

4 0
3 years ago
Is the quotient of two mixed numbers positive ?
zysi [14]
It would be a fraction. 
6 0
3 years ago
Read 2 more answers
There are 5 different French books and 5 different Spanish books. How many ways are there to arrange them on a shelf if
hram777 [196]
B because french and Spanish are alternate soo they grouped and spanish goes second and begin with french book
6 0
3 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
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