D would be the highest value
Answer:
8/ 25
Step-by-step explanation:
hope it helps!
.....
Quadrant is III so, sign would be negative for Sec.
Now, we know, csc = H / P
So, H = 4, P = 3
Calculate for B,
B² = H² - P²
B² = 4² - 3²
B² = 16 - 9
B = √7
We know, sec Ф = H / B = 4 / √7
We can write it as: -4√7 / 7 [ -ve sign for 3rd quadrant ]
In short, Your Answer would be Option B
Hope this helps!
Answer:
![(x+3)^2+(y-2)^2=9](https://tex.z-dn.net/?f=%28x%2B3%29%5E2%2B%28y-2%29%5E2%3D9)
Step-by-step explanation:
<u>Equation of a circle</u>
![(x-a)^2+(y-b)^2=r^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dr%5E2)
where:
- (a, b) is the center
- r is the radius
From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.
Substitute these values into the general form of the equation of a circle:
![\implies (x-(-3))^2+(y-2)^2=r^2](https://tex.z-dn.net/?f=%5Cimplies%20%28x-%28-3%29%29%5E2%2B%28y-2%29%5E2%3Dr%5E2)
![\implies (x+3)^2+(y-2)^2=r^2](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B3%29%5E2%2B%28y-2%29%5E2%3Dr%5E2)
Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:
⇒ radius (r) = 5 - 2 = 3
Substitute the found value of r into the equation:
![\implies (x+3)^2+(y-2)^2=3^2](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B3%29%5E2%2B%28y-2%29%5E2%3D3%5E2)
Therefore, the final equation of the given circle is:
![\implies (x+3)^2+(y-2)^2=9](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B3%29%5E2%2B%28y-2%29%5E2%3D9)
Answer:A
Step-by-step explanation: In (-4,3) -4 is the value of x and 3 is the value of y