4 years ago

Find the center and radius for the circles with the following equation x^2+y^2-4x+6y+11=0

1 answer:

7 0

Rearrange x²+y²-4x+6y=-11 I'll tell you an easy way. take the coefficient of x and divide it by -2 and the coefficient of y and divide it by -2 so -4 ÷-2 = 2 6÷-2= -3 (2,-3) is the center of the circle to know the radius √2² + -3² + -11 =√2 The Radius equals √2

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Evaluate x+2.7 for x=-1.5

jonny [76]

Answer:

1.2

Step-by-step explanation:

First make -1.5 equal to 0.

We'll have to add 1.5, right?

So 1.5 is in 2.7.

So now its 0 + ? = ?

2.7 - 1.5 = 1.2

So 0 + 1.2 = 1.2

Hope this helped.

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Read 2 more answers

MZRSK = x + 53, m KST = x + 109,<br> and mZRST = 156º<br><br><br> Find x.

Dahasolnce [82]

Answer:

$-3 = x$

Step-by-step explanation:

Since we are not given a midpoint, we use the Angle Addition Postulate:

156 = [x + 109] + [x + 53]

156 = 162 + 2x

-162 - 162

_______________

−6 = 2x

___ ___

2 2

−3 = x

[−3 + 53] + [−3 + 109] = 156

50 106

156 = 156 ☑

Therefore, $-3 = x$ is a genuine statement.

I am joyous to assist you anytime.

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