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Mama L [17]
3 years ago
8

Need help not sure if my question is true or false

Mathematics
1 answer:
Alika [10]3 years ago
7 0
The answer is false. The radius is half the diameter, not 2 times it.
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Determine whether the given relation is an implicit solution to the given differential equation. assume that y is a function of
Xelga [282]
Differentiate:x^2 + y^2 = 4 
You get this:2x + 2yy' = 0 
bring the x variable on the other side:2yy' = -2x 
Now divide 2y to leave y' by itself:y' = -2x/2y 
Answer: y' = -x/y 
The given relation is not a implicit solution to the given differential equation.
6 0
3 years ago
A carpenter can install 8 sheets of drywall in 10 minutes. At this rate, how long does it take to install one sheet of drywall?
grigory [225]

Answer:

8/10=60/x

600/8=75 minutes=x

Good day! :)

7 0
2 years ago
Read 2 more answers
What number is 1000 less than 921, 438 and explain your answer
aleksley [76]
The number 1000 less than 921,438 is 920,438. What you do is take 921,438 and subtract 1000 from it.
7 0
2 years ago
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An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
In how many different ways can 4 students be seated with in a row?
DanielleElmas [232]
<span>4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.</span>
8 0
3 years ago
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