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Naddik [55]
3 years ago
11

The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo

ng will it take for the population of the bacteria to reach 800?
Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

16.34 hours

Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

A=P(2)^\frac{t}{24}

Here A =800 is the amount that is needed to reach

P is the initial amount that is 500

We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get

800=500(2)^\frac{t}{24}

On simplification we get

\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}

Taking log on both sides we get

\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}

using \log\frac{m}{n}=\log m-\log n

And \log a^m=m\log a

\Rightarrow\log{8}-\log{5}=\frac{t}{24}\log2

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get

\Rightarrow 0.903-0.698=\frac{t}{24}0.301

\Rightarrow 0.205=\frac{t}{24}0.301

\Rightarrow \frac{0.205}{0.301}\cdot 24=t

\Rightarrow t=16.34

pantera1 [17]3 years ago
5 0

The answer is to this problem would be 10.8.

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