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3 years ago

The velocity of an object includes its speed and____?

Physics

1 answer:

mr_godi [17]3 years ago

6 0

it includes an objects speed and direction

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What is CGS unit of weight

alukav5142 [94]

Answer:

<h3> $\boxed{dyne}$ </h3>

Explanation:

The weight of a body is defined as the force with which it is attracted towards the centre of a planet. A spring balance measures it. It's unit is Newton ( N ) in the SI system and dyne in the CGS system.

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4 0

3 years ago

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A bicyclist starts at point P and travels around a triangular path that takes her through points Q and R before returning to the

REY [17]

Answer:

Displacement by cyclist is zero.

Explanation:

In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.

The bicyclist starts from P and travel through Q and R and returned to P again.

We need to find its displacement.

We know displacement of a body is its difference between its initial position to final position.

Here in the given question the bicyclist returns to P again.

Therefore, total displacement by bicyclist is zero.

Hence, this is the required solution.

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3 years ago

HURRY!!! I only have 14 more minutes

DochEvi [55]

Answer:

B-cells

T-cells

stem cells

Im like 95% sure good luck

Explanation:

I passed biology and science

8 0

3 years ago

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Which of the following accurately describes the way in which a muscle moves?

Vaselesa [24]

<h3><u>Answer</u>;</h3>

B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.

<h3><u>Explanation;</u></h3>

<em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
<em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
<em><u>Filament movement starts at the region or zone where thin and thick filaments overlap. </u></em>
<em><u>Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.</u></em>

7 0

2 years ago

A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

Ilya [14]

Answer with Explanation:

We are given that

Area of loop= $(20\times 20) cm^2=400\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

Resistance, R= $0.1\Omega$

B= $4t-2t^2$

We know that magnetic flux

$\phi=BA$

Emf , $E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid$