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Alex
3 years ago
10

Nearly all physics problems will use the unit m/s^2 for acceleration. Explain why the seconds are squared. Why isn't the unit gi

ven as m/s, as it is for speed
Physics
1 answer:
sertanlavr [38]3 years ago
6 0

Because acceleration is not speed, and speed is not acceleration. 
I'm sure you would not ask "Why isn't temperature given in acres,
as it is for area ?"  Speed and acceleration are different things, so
it's only natural that they have different units.


The magnitude (size) part of acceleration is:

         (how much speed changes) per second.

Are you speeding up ?
Are you traveling (2 meters per second) faster every second ?
Then your acceleration is

           (2 meters per second) per second .

When you write that phrase as an algebraic expression, it's

           (2 m/sec) / sec

and when you simplify that fraction, you get        2 m/sec² .


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A fairgrounds ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follo
Valentin [98]

We know that the acceleration due to gravity g is: g = 9.81 m/s^2

So the centripetal acceleration (w) is:

w^2 = 1.5 g / r

w^2 = 1.5 * (9.81 m/s^2) / 5 m

w = 1.716 rad / s

To convert to rad to rev:

w = (1.716 rad / s) * (1 rev / 2π rad) * (60 s/min)

<span>w = 16.4 rev/min </span>

3 0
3 years ago
A hair dryer uses 72,000 joules of energy in 60 seconds. What is the power of this hair dryer?
Salsk061 [2.6K]
Divide energy by time, that is, 72000/60=1200 watts.
7 0
3 years ago
Read 2 more answers
if pes represents the potential energy stored in a spring in kg•m^2/s^2 and x represents the change in the springs length from i
musickatia [10]
Unit for x - the change in the spring length:
x = [ m ]
PE s =  1/2 k x²
[ kg m² / s² ] = 1/2 k * [ m² ]   /: m²
k = [ kg / s² ]
Answer: The unit for spring constant k is kg/ s²
8 0
3 years ago
A large object las Less of an attraction on a smaller <br><br> True <br> False
leva [86]
Do you mean ‘Does a larger object have less attraction than a smaller object?’ If so, then the answer is objects with a larger mass exert more attraction while objects with a smaller mass have less attraction.
6 0
3 years ago
Can you please help me with these physics displacement questions? If you can only do one, that is okay
Brut [27]

#3).  Your drawing in the lower right corner is correct.  You're headed down the right road, but ran out of gas and just stopped.

Radius of the circle = 1.5 km

Circumference of the whole circle = (2·π·radius) = 9.42 km

Distance = 3/4 of the way around it = 7.07 km .

Displacement = the straight line from the West point to the North point.  The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°).  I'll let you figure out why these numbers.

#4).  What if you walk 1 mile East and then 1 mile West ?  You got a good workout, and you're back home where you started !  Your distance is 2 miles, and your displacement is zero.

The whale had a good workout too.  She swam (6.9 + 1.8 + 3.7) = 12.4 km.  She's sweating and tired.  Her total distance during that workout is 12.4 km.  

Her displacement is the line from start-point to end-point.  How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.

(6.9E + 1.8W + 3.7E)  =  (10.6 E) + (1.8 W) . . . That adds up to  8.8 East !  That's where she ends up.  That's her displacement ... 8.8 km East of where she started.  Since we're only talking about displacement, we don't care HOW she got there.  She might have been swimming big 20-km circles all day.  We don't know.  All we know is that she ended up 8.8 km East of where she started.


7 0
3 years ago
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