Answer:
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Answer:
F = ⅔ F₀
Explanation:
For this exercise we use Coulomb's law
F = k q₁q₂ / r²
let's use the subscript "o" for the initial conditions
F₀ = k q² / r²
now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r
we substitute
F = k 4q² / 9 r²
F = k q² r² 4/9
F = ⅔ F₀
C. It depends on the medium
Answer:
When does the radioactive decay of a radioisotope stop? Give one example. An unstable isotope continues the decay process until it reaches a stable form. One example is the decay of carbon-14 to nitrogen-14.
Explanation: