Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.
Step-by-step explanation:
Let x represent the number of minutes of long distance call that one makes.
The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be
2.10 + 0.45(x - 3)
Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as
2.10 + 0.45(x - 3) ≤ 6.15
2.10 + 0.45x - 1.35 ≤ 6.15
0.75 + 0.45x ≤ 6.15
0.45x ≤ 6.15 - 0.75
0.45x ≤ 5.4
x ≤ 5.4/0.45
x ≤ 12
Answer:
Dequan walks 5 miles per day.
Step-by-step explanation:
So solve this problem, we just need to divide 20 miles by 4 days.
20 ÷ 4 = 5
Therefore, Dequan walks 5 miles per day.
Hope this helps! :D
Answer:
The probability that the sample mean will lie within 2 values of μ is 0.9544.
Step-by-step explanation:
Here
- the sample size is given as 100
- the standard deviation is 10
The probability that the sample mean lies with 2 of the value of μ is given as

Here converting the values in z form gives

Substituting values

From z table

So the probability that the sample mean will lie within 2 values of μ is 0.9544.
9y-8y-y= 9-8-1 = 0y =0
subtract all like terms
Answer:
a. 125 – 7d
Step-by-step explanation:
Let d be the number of days.
<u>Given the following data;</u>
Total distance (month) = 125 miles
Distance covered per day = 7 miles
To determine how many miles he has left to run after running for "d" days, this mathematical expression can be used;
Total distance - distance covered per day = number of miles remaining
