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kow [346]
3 years ago
11

For the triangle shown, various lengths of x, y, and 2 are given Find the missing measurements for the three triangles.

Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

If x = 5, than y = 5, and z = 5(sqrt)2

If z = 10, than x and y = 5(sqrt)2

If y = 3(sqrt)2, than x = 3(sqrt)2, and z = 6

If x = 1/4, than y = 1/4, and z = (sqrt)2/4

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tigry1 [53]

Answer: y=4x+7 is the equation

5 0
3 years ago
I need help with multiplying polynomials using foil<br><br> Example <br> (X+5)(x-6)
MArishka [77]
Well (x+5)(×-6)
x*x =x2
x*-6=-6x
x*5 = 5x
5*-6= -30
add them all together to get x2-x-30.
I hope this is what you were asking
3 0
3 years ago
If the radius of a circle is doubled in length, the circumference of the circle is....
Klio2033 [76]
<span>If the radius of a circle is doubled in length, the circumference of the circle is <span>B. doubled.
</span>C = 2</span><span>πr - this is the equation for circle. So if you double the radius, its circumference also doubles.</span>
<span>
</span>
5 0
3 years ago
Read 2 more answers
2. Find the general relation of the equation cos3A+cos5A=0
mars1129 [50]
<h2>Answer:</h2>

A=\frac{\pi}{8}+\frac{n\pi}{4}or\ A=\frac{\pi}{2}+n\pi

<h2>Step-by-step explanation:</h2>

<h3>Find angles</h3>

cos3A+cos5A=0

________________________________________________________

<h3>Transform the expression using the sum-to-product formula</h3>

2cos(\frac{3A+5A}{2})cos(\frac{3A-5A}{2})=0

________________________________________________________

<h3>Combine like terms</h3>

2cos(\frac{8A}{2})cos(\frac{3A-5A}{2})=0\\\\  2cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Divide both sides of the equation by the coefficient of variable</h3>

cos(\frac{8A}{2})cos(\frac{-2A}{2})=0

________________________________________________________

<h3>Apply zero product property that at least one factor is zero</h3>

cos(\frac{8A}{2})=0\ or\ cos(\frac{-2A}{2})=0

________________________________________________________

<h2>Cos (8A/2) = 0:</h2>

<h3>Cross out the common factor</h3>

cos\ 4A=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

4A=\frac{\pi}{2}or\ 4A=\frac{3\pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

4A=\frac{\pi}{2}+2n\pi \ or\\ \\ 4A=\frac{3 \pi}{2}+2n \pi\\ \\A=\frac{\pi}{8}+\frac{n \pi}{4\\}

________________________________________________________

<h2>cos(-2A/2) = 0</h2>

<h3>Reduce the fraction</h3>

cos(-A)=0

________________________________________________________

<h3>Simplify the expression using the symmetry of trigonometric function</h3>

cosA=0

________________________________________________________

<h3>Solve the trigonometric equation to find a particular solution</h3>

A=\frac{\pi }{2}\ or\ A=\frac{3 \pi}{2}

________________________________________________________

<h3>Solve the trigonometric equation to find a general solution</h3>

A=\frac{\pi}{2}+2n\pi\ or\ A=\frac{3\pi}{2}+2n\pi,n\in\ Z

________________________________________________________

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{2}+n\pi

________________________________________________________

<h2>A = π/8 + nπ/4 or A = π/2 + nπ, n ∈ Z</h2>

<h3>Find the union of solution sets</h3>

A=\frac{\pi}{8}+\frac{n\pi}{4}\ or\ A=\frac{\pi}{2}+n\pi ,n\in Z

<em>I hope this helps you</em>

<em>:)</em>

5 0
2 years ago
Im so confused pls help
timama [110]
Answer:

a = 49°

Explanation:

You use the rule ‘exterior angle of a triangle’ which states that the exterior angle is equal to the sum of the two opposite interior angles.

To put it mathematically:

a + a = a + 49° (Ext angles of triangle)
a = a - a + 49°
a = 49°
5 0
3 years ago
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