A (103)(109)
=103*109
=(10*10*10)*(10*10*10*10*10*10*10*10*10)
=10*10*10*10*10*10*10*10*10*10*10*10
=1012
=1000000000000
c.1e+23
Answer: y = (-3x/2) + 1
Step-by-step explanation:
From the standard equation y = mx + c, the slope of the equation is 2/3. Therefor slope of a line perpendicular to it will be -3/2.
Hence the equation will be
y = (-3x/2) + c
As this line passes through (-2,4), putting these values in this equation gives c = 1.
Hence the answer is y = (-3x/2) + 1
Dr/dt= 8cmM-¹
dA/dt = ?
but A= πr²
so dA/dr =2πr
but recall
dA/dt = dA/dr • dr/dt
dA/dt = 2πr • 8cmM-¹
dA/dt = 2×π×39 ×8 = 624cm²M-1
To solve this we are going to use the formula for the area of a circle:

where

is the area of the circle

is the diameter of the circle
We know from our problem that the area of our circle is 10 inches long, so

. Lets replace that value in our formula to find

:


We can conclude that the correct answer is: 78.54 square inches, or in centimeters: 506.7 square cm.
Standard form for y+7=-2/5(x-10) is y=-7-2/5(x-10)