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3 years ago

Plzzzzzzzz help meeeee

Mathematics

1 answer:

Pani-rosa [81]3 years ago

5 0

Answer:

38 in²

Step-by-step explanation:

The area (A) of a trapezium is calculated using the formula

A = $\frac{1}{2}$ h (a + b)

where a, b are the parallel bases and h the perpendicular height

here a = 12, b = 7 and h = 4, hence

A = 0.5 × 4 × (12 + 7) = 2 × 19 = 38 in²

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The speed of boat in still water is 15km/hr if needs 4 more his to travel 63 km against the current of a river than it needs to

hram777 [196]

Answer:

$\frac{63}{15 - c} - \frac{63}{15 + c} = 4$

Step-by-step explanation:

The systems of equations are

Let us assume the rate of the current be c

Now actual speed against the current is (15 - c)

And, the actual speed with the current is (15 + c)

Here we applied the time formula i.e. distance by speed

Also the upstream time - downstream time = 4

Now the equations are

$\frac{63}{15 - c} - \frac{63}{15 + c} = 4$

5 0

3 years ago

Please help! Correct answer only please! I need to finish this assignment by tomorrow.

pentagon [3]

Answer:

0.779

Step-by-step explanation:

1(58)+2(24)+3(8)+4(39)=286

286/367=0.779

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3 years ago

A school choir has 36 members. There are three times as many underclassmen as seniors. How many seniors are in the choir?

joja [24]

108 if my maths is correct

5 0

3 years ago

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What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

Equation :-

$\implies log_e {(x^2-25)}= 0$

In general :-

If we have a logarithmic equation as ,

$\implies log_a b = c$

Then this can be written as ,

$\implies a^c = b$

In a similar way we can write the given equation as ,

$\implies e^0 = x^2 - 25$

Now also we know that $a^0 = 1$ Therefore , the equation becomes ,

$\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}$

Hence the Solution of the given equation is ±√26.

6 0

3 years ago

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0

3 years ago

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