Answer:
-3
Step-by-step explanation:
3(-2)/2
-6/2 = -3
would be a basis for if
(1) the vectors in are independent, and
(2) the vectors span .
These vectors are not linearly independent because if , , and , we have
so is not a basis for .
y-5=-6/5(x+2)
m=(5+1)/(-2-3)
m=6/-5
D