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3 years ago

Can anyone solve this for me pleaee ??

Mathematics

1 answer:

Nonamiya [84]3 years ago

3 0

Let Poly = X

Andy gets twice as much as Poly so Andy = 2X

Pheobe gets three times as much as Andy, so she is 3(2x) = 6X

Now add them together to equal 270:

X + 2X + 6X = 270

Simplify:

9X = 270

Divide both sides by 9:

X = 270 /9

X = 30

Poly = X = 30

Andy = 2X = 2(30) = 60

Pheobe = 6X = 6(30) = 180

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How would you solve 4n-2n=4?

Nezavi [6.7K]

Answer:

n = 2

Explanation:

Simplify both sides of the equation

4n − 2n = 4

4n + −2n = 4

(4n + −2n) = 4 (Combine Like Terms)

2n = 4

Divide both sides by 2

2n / 2 = 4 / 2

n = 2

3 0

4 years ago

Read 2 more answers

A chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium to obtain a 70-milliliter mixture.Write th

Verdich [7]

Answer:

$S(x)=-0.4x+42$

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.

Step-by-step explanation:

It is given that a chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium-iodine to obtain a 70-milliliter mixture.

Let x be the number of milliliters of the 20% sodium-iodine.

Number of milliliters of the 60% sodium-iodine = 70-x

The amount of sodium iodine in the mixture is 20% of x and 60% of (70-x).

$S(x)=0.20x+0.60(70-x)$

$S(x)=0.2x+42-0.6x$

$S(x)=-0.4x+42$

Therefore,the required function is $S(x)=-0.4x+42$ .

Substitute x=50 in the above equation.

$S(50)=-0.4(50)+42$

$S(50)=22$

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.

4 0

4 years ago

Your local radio station is having their yearly music player and concert ticket giveaway . For one minute every 5th caller will

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3 years ago

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Will a stand that can hold up to 40 pounds support a 21-kilogram television?

LUCKY_DIMON [66]

1 kg = 2.20 pound
21kg = 21 x 2.20 = 46.2 pounds

Since the tv is heavier than the stand can support. The stand will not support the tv.

5 0

4 years ago

A 75% increase followed by a 33 1/2% decrease

o-na [289]

After 75% increase followed by a 33 1/2% decrease the net increased is 16.375%.

<u>Solution:</u>

Need to determine net percentage increase or decrease when a value is increased by 75% and then decreased by $33 \frac{1}{2} \%$ that is 33.5%.

Let’s assume initial value be represented by variable x.

$75 \% \text { decrease means } x+75 \% \text { of } x=x+\frac{75}{100} x=x+0.75 x=1.75 x$

Now there is decrease of 33.5%

$\begin{array}{l}{33.5 \% \text { decrease means } 1.75 x-33.5 \% \text { of } 1.75 x=1.75 x-\frac{33.5}{100} \times 1.75 x} \\\\ {=1.75 x-(0.335 \times 1.75) x=1.75 x-0.58625 x} \\\\ {=1.16375 x}\end{array}$

$\text { So increase in percentage }=\frac{\text { final value-initial value}}{\text { intial value }}$

$=\frac{1.16375 x-x}{x} \times 100=16.375 \%$

Hence after 75% increase followed by a $33 \frac{1}{2} \%$ decrease the net increased is 16.375%.

8 0

3 years ago

Can anyone solve this for me pleaee ??​

Can anyone solve this for me pleaee ??