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3 years ago

The amount of matter (mass) in a given unit volume

Physics

1 answer:

maxonik [38]3 years ago

6 0

Answer:

Density is the mass of a substance per unit volume. Volume is the amount of space an object occupies.

Explanation:

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Advocard [28]

Because an earthquake happens when two of the atomic plates rub together .

Hopes this helps. PLZ MARK BRAINIEST

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3 years ago

even though the sun has _____mass than earth the moon orbits earth because it's closer to earth than to the sun

olga2289 [7]

Even though the san has more mass than earth the moon orbits earth because it's closer to earth than to the sun.

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2 years ago

Read 2 more answers

A 3.47-m rope is pulled tight with a tension of 106 N. A wave crest generated at one end of the rope takes 0.472 s to propagate

konstantin123 [22]

Answer:

The mass of the rope is 1.7 kg.

Explanation:

Given;

length of the rope, L = 3.47 m

tension on the rope, T = 106 N

period of the wave, t = 0.472 s

frequency of the is calculated as;

$f = \frac{1}{t} \\\\f = \frac{1}{0.472} \\\\f = 2.1186 \ Hz$

the speed of the wave is calculated as;

$v = \sqrt{\frac{T}{\mu} }$

where;

v is speed of the wave = fλ

λ is the wavelength

μ is mass per unit length

$f\lambda = \sqrt{\frac{T}{\mu} } \\\\f(2l) = \sqrt{\frac{T}{\mu} } \\\\2fl = \sqrt{\frac{T}{\mu} } \\\\(2fl)^2 = \frac{T}{\mu}\\\\4f^2l^2 =\frac{T}{\mu}\\\\\mu = \frac{T}{4f^2l^2}\\\\\frac{m}{l} = \frac{T}{4f^2l^2}\\\\m = \frac{T}{4f^2l}\\\\m = \frac{106}{4(2.1186)^2(3.47)}\\\\m = 1.7 \ kg$

Therefore, the mass of the rope is 1.7 kg.

6 0

3 years ago

96 K = _____ -177°C 0°C 96°C 369°C

charle [14.2K]

-177 C !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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3 years ago

A quantity of hot water at 91°C and another cold one at 12°C.

Burka [1]

Answer:

$m_{cold}=567kg\\\\m_{hot}=233kg$

Explanation:

Hello!

In this case, since equilibrium temperature problems involve the mass, specific heat and temperature change for the substances at different temperatures, we can write:

$m_{cold}C_{cold}(T_{eq}-T_{cold})=-m_{hot}C_{hot}(T_{eq}-T_{hot})$

Thus, since we are talking about water and they both have the same specific heat, we can write:

$m_{cold}(T_{eq}-T_{cold})=-m_{hot}(T_{eq}-T_{hot})$

Now, we plug in the temperatures to obtain:

$m_{cold}(35-12)+m_{hot}(35-91)=0\\\\23m_{cold}-56m_{hot}=0$

Next, since the total volume of water is 800 L, since it has a density of 1kg/L, we infer the total mass is 800 kg; that is why we can write a 2x2 system of simultaneous equations:

$\left \{ {{23m_{cold}-56m_{hot}=0} \atop {m_{cold}+m_{hot}=800}} \right.$

Thus, the masses of both cold and hot water turn out:

$m_{cold}=567kg\\\\m_{hot}=233kg$

Best regards!

7 0

2 years ago