Let the tension in the thread will be at angle theta
now by force balance in x and y directions we can say
![17 cos\theta = 18 cos60](https://tex.z-dn.net/?f=17%20cos%5Ctheta%20%3D%2018%20cos60)
![17 cos\theta = 9](https://tex.z-dn.net/?f=17%20cos%5Ctheta%20%3D%209)
![\theta = 58.03 degree](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2058.03%20degree)
now for the height of the kite we can use
![h = L sin\theta](https://tex.z-dn.net/?f=h%20%3D%20L%20sin%5Ctheta)
![h = 38 sin58.03](https://tex.z-dn.net/?f=h%20%3D%2038%20sin58.03)
![h = 32.23 m](https://tex.z-dn.net/?f=h%20%3D%2032.23%20m)
<em>so it will be at height 32.23 m from ground</em>
The chemical symbol always begins with a capital letter.
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There is a lot of glare off of the ice, due to the sun and it also is always good to have eye protection in case you fall face first :P
Answer:
B. NET force: 2 resultant motion: left
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C. Net force: 3 Resultant motion: Left
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D. Net Force: 7 Resultant motion: right
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E. Net Force:0 resultant motion: NO MOTION
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F. NET Force: 3 resultant motion: Down
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G. NET FORCE: 10 resultant motion: up
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H. Net force: 3 Resultant motion: left
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I. Net force: 50 Resultant motion: right
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J. NET FORCE: 75 Resultant motion: down
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K. Net force :200 Resultant motion: Right
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L. Net force: 0 resultant motion:No motion
Explanation: