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Paraphin [41]
3 years ago
14

After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work. What type of circuit

does this traffic situation model?
Physics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

C

Explanation:

a parallel circuit because there is more than one path

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A planned high-speed train between Houston and Dallas will travel a distance of 386 kilometers in 5.40 × 10^3 seconds. What is t
Mazyrski [523]

¡Hellow!

For this problem, first, lets convert the seconds in hours:

5,4x10³\rightarrow 5400

h = sec / 3600

h = 5400 s / 3600

h = 1,5

Let's recabe information:

d (Distance) = 386 km

t (Time) = 1,5 h

v (Velocity) = ?

For calculate velocity, let's applicate formula:

                                                    \boxed{\boxed{\textbf{d = v * t} } }

Reeplace according we information:

386 km = v * 1,5 h

v = 386 km / 1,5 h

v = 257,33 km/h

The velocity of the train is of <u>257,33 kilometers for hour.</u>

<u></u>

Extra:

For convert km/h to m/s, we divide the velocity of km/h for 3,6:

m/s = km/h / 3,6

Let's reeplace:

m/s = 257,33 km/h / 3,6

m/s = 71,48

¿Good Luck?

7 0
3 years ago
Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge
NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is V=\frac{1}{4\pi\epsilon} \frac{q}{d}

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0
3 years ago
How are strong nuclear forces and weak nuclear forces alike
Nesterboy [21]
Even tho one is stronger then the other... they are both alike because they are still nuclear forces.
6 0
3 years ago
A block of mass 9.2kg rests on a slope an angle of 26.9∘ relative to the horizontal. What is the size of the contact force norma
Olegator [25]

Answer:

80.4 N

Explanation:

As the block is at rest on the slope, it means that all the forces acting on it are balanced.

We are only interested in the forces that act on the block along the direction perpendicular to the slope. Along this direction, we have two forces acting on the block:

- The normal reaction N (contact force), upward

- The component of the weight of the block, mg cos \theta, downward, where m is the mass of the block, g is the gravitational acceleration and \theta is the angle of the incline

Since the block is in equilibrium along this direction, the two forces must balance each other, so they must be equal in magnitude:

N=mg cos \theta

And by substituting the numbers into the equation, we find the size of the contact force normal to the slope:

N=(9.2 kg)(9.8 m/s^2)(cos 26.9^{\circ})=80.4 N

6 0
3 years ago
A laser beam enters a 16.5 cm thick glass window at an angle of 58.0° from the normal. The index of refraction of the glass is 1
ivann1987 [24]

Answer:

using Snells law

Oi = angle of incidence = 58.0°

    ni = index of refraction of air = 1.0003

    nr = index of refraction of glass = 1.47

    c = speed of light in vacuum = 3 x 10^8 m/s

    Or = angle of refraction = ?

ni(sinOi) = nR (sinOr)

ni( sinOi)/ nR = sinOr

arcsin(ni(sin0i))/nR = Or

arcsin( 1.0003(sin58.0)) / 1.47

Or = 35.25°

Explanation:

5 0
3 years ago
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