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anastassius [24]
3 years ago
12

What is the equivalent resistance of the circuit? A: 0.500 ohms B: 120.0 ohms C: 2.00 ohms D: 60.0 ohms

Physics
2 answers:
Gwar [14]3 years ago
7 0

Answer:

Option D. is the correct choice.

Explanation:

Resistances connected in series add up to give equivalent resistance.

R_eq = 10+20+30 = 60 ohm

Best Regards!

Sonja [21]3 years ago
5 0

Answer:

Option D

Explanation:

I just took the T eSt on ApEx

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What is an object doing at the moment its instantaneous acceleration is zero?
Oliga [24]

Answer: Option A

Explanation:

Acceleration is defined as the rate of change of the vellocity.

Then, if the acceleration is equal zero, the object has a constant velocity or a velocity equal to zero (also constant, of course)

Then, te correct option would be option A; resting, because an object resting has instantaneuos acceleration of zero.

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3 years ago
An aluminum cup of mass 150 g contains 800 g of water in thermal equilibrium at 80.0°C. The combination of cup and water is cool
gladu [14]

Answer:

Heat Flow Rate : ( About ) 87 W

Explanation:

The heat flowing out of the system each minute, will be represented by the following equation,

Q( cup ) + Q( water ) = m( cup ) * c( al ) * ΔT + m( w ) * c( w ) * ΔT

So as you can see, the mass of the aluminum cup is 150 grams. For convenience, let us convert that into kilograms,

150 grams = .15 kilograms - respectively let us convert the mass of water to kilograms,

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Now remember that the specific heat of aluminum is 900 J / kg * K, and the specific heat of water = 4186 J / kg * K. Therefore let us solve for " the heat flowing out of the system per minute, "

Q( cup ) + Q( water ) = .15 * ( 900 J / kg * K )  * 1.5 + .8 * ( 4186 J / kg * K ) * 1.5,

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3 years ago
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Rudik [331]

Answer:

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cause logic

8 0
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A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple h
babunello [35]

Answer:

he maximum frequency occurs when the denominator is minimum

 f’= f₀  \frac{343}{343 + v_s}

Explanation:

This is a doppler effect exercise, where the sound source is moving

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           f ’=f_o  \frac{v}{v+v_{sy}}  Alexandrian source of the observer

the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects

          f’= f₀  \frac{343}{343 + v_s}

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