All categories

3 years ago

Which ones are non-linear and which ones are linear?

Mathematics

2 answers:

loris [4]3 years ago

8 0

Answer:

Linear:y=x,Nonlinear:y=x^2,y=x^3

Step-by-step explanation:

A linear function goes in a straight line,a nonlinear function doesn't.

Alex787 [66]3 years ago

6 0

Answer:

y=x

Step-by-step explanation:

the other two are not linear because any equation with an exponent is not linear

You might be interested in

Ariana wants to ride her bicycle 37 miles this week. She has already ridden 14 miles. If she rides for 5 more days, write and so

lakkis [162]

Answer:

4.6 miles for 5 days.

Step-by-step explanation:

37 - 14 = 23

23 divided by 5 = 4.6

7 0

3 years ago

Prove that the two circles shown below are similar. (10 points) Circle C is shown with a center at negative 3, 1 and a radius of

Tanya [424]

Answer:

Well, in reality, all circles are similar to each other. They will all have the same angles, and they don't really have side lengths. So, they are similar.

But to PROVE they are similar, we will transform Circle C to match circle E.

Circle C has a center at (-3, 1), and Circle E has a center of (4, 9). For Circle C to have the same center as Circle E, we will translate Circle C 7 units to the right, and 8 units up.

Since Circle C has a radius of 4, and Circle E has a radius of 3, dilate Circle C by a factor of 3/4. That way, the radius is 3 units as well.

And there you go! The two circles will map perfectly on top of each other.

Hope this helps!

5 0

3 years ago

The stem-and-leaf plot shows the weights (in pounds) of yellowfin tuna caught during a fishing contest.

AysviL [449]

Answer:

The answer is "87 pounds".

Step-by-step explanation:

Please find the complete question in the attached file.

4 0

3 years ago

Log*subscript*(3x − 2) 4096 = 3<br><br> I got x= negative 6 is this correct??

Brut [27]

Remember

$log_a(b)=c$ translates to $a^c=b$
and
$log_a(b^c)=clog_a(b)$
so

4096=16^3
$log_{3x-2}(4096)=3$
$log_{3x-2}(16^3)=3$
$3log_{3x-2}(16)=3$
divide both sides by 3
$log_{3x-2}(16)=1$
translate
$(3x-2)^1=16$
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6

8 0

4 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

4 years ago