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dem82 [27]
3 years ago
9

The sum of two numbers is 78. Their difference is 32. Write a system of equations that describes this situation. Solve by elimin

ation to find the two numbers. x + y = 32 y – x = 78 50 and 24 x – y = 78 x + y = 32 54 and 24 x + y = 78 x – y = 32 55 and 23
Mathematics
1 answer:
Triss [41]3 years ago
8 0
Not sure what the extra numbers and equation are, but I'll just solve it.*Note* first number and second number isn't really assigned, just shows one of the numbers of the two*
F= first number
S= second number
F+S=78
F-S= 32
Now, you want to eliminate F, so you'll multiply the first equation by -1
-(F+S=78)
F-S=32
-F-S=-78
F-S=32
-2S=-46
S=23
Now plug in the number to one of the equations.
F+23=78
78-23= 55
The two numbers are 55 and 23.
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What is the solution to the proportion 3y-8/12=y/5? can someone help me do this?
RideAnS [48]
   
\displaystyle\\
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5(3y-8)=12y\\\\
15y-40=12y\\\\
3y = 40\\\\
\boxed{y =  \frac{40}{3}}



3 0
3 years ago
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What are two numbers that has the product of 40 but has the sum of 13
Maksim231197 [3]

Answer:

8 and 5

Step-by-step explanation:

3 0
3 years ago
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Hey, I need help with questions 1 and 2, if anyone can help, please? thanks!
Eva8 [605]

The correct works are:

  • Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3.
  • \frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

Blue(s + h) = 2(s + h)^2 + 3

Evaluate the exponent

Blue(s + h) = 2(s^2 + 2sh + h^2) + 3

Expand the bracket

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

Evaluate the like terms

\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

brainly.com/question/13136492

4 0
2 years ago
The period of a function is 4 pi how many cycles of the function occur in a horizontal length of 12 pi
eduard

Answer:

3 cycles

Step-by-step explanation:

in one period, you have one full cycle

because the period for this function is 4pi, you have one cycle per 4pi

if you have a total of 12pi, you would have 3 cycles (12pi/4pi=3)

hope this helps!

3 0
3 years ago
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I need help doing this can somebody please help?! It’s number 2.
stepladder [879]
Yes, if you solve both problems they come out to the same answer.
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