Answer:
C. Town A has the greater average number of dogs per neighborhood.
Step-by-step explanation:
First, find Town A's average number of dogs per neighborhood. Since the graph is a straight line, you can find the number of dogs per neighborhood by dividing a given y-value by its x-value counterpart:
(4,60)
60 dogs / 4 neighborhoods
<u>15 dogs / neighborhood.</u>
Now, we must find the average number of dogs per neighborhood in Town B. Since the equation is y = 10x, where x is the number of neighborhoods, in 1 neighborhood, there are 10 dogs:
<u>10 dogs / neighborhood.</u>
Finally, compare the two values:
15 > 10
<u>C. Town A has the greater average number of dogs per neighborhood.</u>
let's firstly find the equation of the parabola, bearing in mind that x-intercepts or solutions/zeros/roots means y = 0.
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2-9 \\\\\\ \textit{we also know that } \begin{cases} x=0\\ y=-6 \end{cases}\implies -6=a(0-1)^2-9\implies 3=a(-1)^2](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D1%5C%5C%20k%3D-9%20%5Cend%7Bcases%7D%5Cimplies%20y%3Da%28x-1%29%5E2-9%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20x%3D0%5C%5C%20y%3D-6%20%5Cend%7Bcases%7D%5Cimplies%20-6%3Da%280-1%29%5E2-9%5Cimplies%203%3Da%28-1%29%5E2)
![\bf 3=a\qquad \qquad \textit{therefore}\qquad \qquad \boxed{y=3(x-1)^2-9} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{y}{0}=3(x-1)^2-9\implies 9=3(x-1)^2\implies \cfrac{9}{3}=(x-1)^2\implies 3=(x-1)^2 \\\\\\ \pm\sqrt{3}=x-1\implies \pm\sqrt{3}+1=x\implies x= \begin{cases} \sqrt{3}+1\\ -\sqrt{3}+1 \end{cases}\implies x\approx \begin{cases} 2.73\\ -0.73 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%203%3Da%5Cqquad%20%5Cqquad%20%5Ctextit%7Btherefore%7D%5Cqquad%20%5Cqquad%20%5Cboxed%7By%3D3%28x-1%29%5E2-9%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7By%7D%7B0%7D%3D3%28x-1%29%5E2-9%5Cimplies%209%3D3%28x-1%29%5E2%5Cimplies%20%5Ccfrac%7B9%7D%7B3%7D%3D%28x-1%29%5E2%5Cimplies%203%3D%28x-1%29%5E2%20%5C%5C%5C%5C%5C%5C%20%5Cpm%5Csqrt%7B3%7D%3Dx-1%5Cimplies%20%5Cpm%5Csqrt%7B3%7D%2B1%3Dx%5Cimplies%20x%3D%20%5Cbegin%7Bcases%7D%20%5Csqrt%7B3%7D%2B1%5C%5C%20-%5Csqrt%7B3%7D%2B1%20%5Cend%7Bcases%7D%5Cimplies%20x%5Capprox%20%5Cbegin%7Bcases%7D%202.73%5C%5C%20-0.73%20%5Cend%7Bcases%7D)
Answer:9 1/2 and 5 1/2
I hope that’s what your looking for
3x + 9= 3 (x + 3)
x + 9 + x= 2x + 9
Answer:
Not very good at these but prob 1st and last
Step-by-step explanation:
