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3 years ago

Create the equation of a line that is perpendicular to 2y=14+(2/3) x and passes through the point (-2,8).

Mathematics

1 answer:

anzhelika [568]3 years ago

6 0

Answer:

y = -3x +2

Step-by-step explanation:

If you divide the equation for the given line by 2, it will be in slope-intercept form:

y = (1/3)x +7

This tells you its slope is 1/3. The slope of the perpendicular line is the negative reciprocal of this: -1/(1/3) = -3. The point-slope form of the equation for the perpendicular line can be written as ...

y = m(x -h) +k . . . . . line with slope m through point (h, k)

Your line is ...

y = -3(x -(-2)) +8

y = -3x +2

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3 years ago

The graph of y=x^3 is transformed as shown in the graph below. With. Equation represents the transformed function

taurus [48]

Answer: y' = (-x)^3 - 4

Step-by-step explanation:

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3 years ago

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Read 2 more answers

Help plzz division math prob

leva [86]

g(x) = x - 3 = 0

g(x) = x = 3

f(x) = 2x^3 + x - 4

f(3) = 2(3)^3 + 3 - 4

f(3) = 2(27) - 1

f(3) = 54 - 1

f(3) = 53

The remainder when f(x) is divided by x - 3 is <u>53</u>.

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3 years ago