Answer:
6. 16 meters^2, 16 meters
7. 100 milimieters^2, 40 milimeters
9. 56 centimeters^2, 30 centimeters
10. 49 inches^2, 28 inches
11. 9 meters^2, 12 meters
12. 72 yards^2, 36 yards
Step-by-step explanation:
s is for a square
A=s^2
P=4s
l+w is for a rectangle
A=lw
P=2l+2w
6. A=4^2
A= 16 meters^2
P=4*4
P= 16 meters
7. A=10^2
A=100 milimieters^2
P=4*10
P= 40 milimeters
9. A=8*7
A= 56 centimeters^2
P=2(8)+2(7)
P=30 centimeters
10. A=7^2
A=49 inches^2
P=4*7
P=28 inches
11. A= 3^2
A=9 meters^2
P=4*3
P= 12 meters
12.
A=12*6
A=72 yards^2
P= 2(12)+2(6)
P= 36 yards
Let me know if you have any questions. Also, don't forget units!
Answer:
x = 50
Step-by-step explanation:
add all terms and set sum equal to 360
the 'hint' of (n-2)180 determines how many degrees there are inside the polygon; if 'n' equals the number of sides and the polygon has 4 sides then sum of interior angles is (4-2)180 or 2x180 which is 360
x + 10 + 3x + x + 2x = 360
combine like terms to get: 7x + 10 = 360
7x = 350
x = 50
Rationalize the numerator:
This is continuous at 
, so we can evaluate the limit directly by substitution:
The sample mean is the sum of the sample values divided by the number of them:
(7 +7 +10 +6 +9 +6 +8 +7.5 +8.5 +8)/10 = 77/10 = 7.7
The sample mean is 7.7.
Answer:
correct option is △XYZ ~ △X'Y'Z'.
Step-by-step explanation:
since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.
as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.
As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5.
ΔXYZ was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.
i.e., △XYZ ~ △X'Y'Z'.
