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weeeeeb [17]
3 years ago
6

What is the frequency of a red light with a wavelength of 6.98 x 10^-6

Chemistry
1 answer:
nevsk [136]3 years ago
4 0

Answer:

frequency of light = 4.2\times 10^{-13}

Explanation:

we know that relation between frequency and wavelength of light is

frequency × wavelength = speed of light.

therefore frequency = \frac{c}{wavelength}

                                  = \frac{3\times 10^{8}}{6.98\times 10^{-6}}

                                  =4.2\times 10^{-13}

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Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.
valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 29.0°C

Final temperature of the water = T_f  = 46.0°C

Change in temperature ,\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C

Putting in the values, we get:

Q=7.40g\times 4.184J/g^0C\times 17.0^0C

Q=526J

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0
3 years ago
What does the MC1R gene code for
zlopas [31]
The MC1R gene provides instructions for making a protein called the melanocortin 1 receptor. This receptor plays an important role in normal pigmentation. The receptor is primarily located on the surface of melanocytes, which are specialized cells that produce a pigment called melanin.
5 0
3 years ago
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What is atomic theory?​
shusha [124]

Answer: the theory that all matter us made up of tiny invisible particles. Hope that help you out :)

Explanation:

3 0
3 years ago
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At what temperature would a 1.30 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86
Setler [38]

Answer:

-4.59°C

Explanation:

Let's see the formula for freezing point depression.

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Freezing constant. For water if 1.86°C/m

m = molality (moles of solute in 1kg of solvent)

i = Van't Hoff factor.

0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9

Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)

Freezing T° of solution = - (1.86°C/m .  1.30m . 1.9) → -4.59°C

NaCl →  Na⁺  +  Cl⁻

4 0
3 years ago
1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
Kazeer [188]

1. Answer:

1.0 × 10–9 M OH–

Explanation:

pH = -Log[H+]

pOH = -Log[OH-]

But;

pH + pOH = 14

Therefore;

[H+] + [OH-] = 1.0 × 10^-14 M

Therefore;

[OH-] = 1.0 × 10^-14 M - (1.0 × 10^–5 M)

         = 1.0 × 10^-9 M OH–

2. Answer;

pH = 7.28

Explanation;

pH = -Log[H3O+]

Given;

[H3O+] = 5.2 × 10^–8 M

Therefore;

pH = - log [5.2 × 10^–8 M]

     = 7.28

The pH is 7.28

3 0
3 years ago
Read 2 more answers
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