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2 years ago

For the graph x = 12 find the slope of a line that is perpendicular to it and the slope of a line parallel to it.

1 answer:

3 0

The slope of a line perpendicular to this is (y=a number) 0. That's because the change in the x would be 0, because it would be y=3 or something like that.

The slope of a line parallel to this is undefined. That's because it has the same slope as this line, and this line has a slope of undefined.

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If Cos 30° equals rad 3/2 then the sin 60° equals a) 0 b) 1/2 c) rad 3/2 d) 1

vovangra [49]

Answer:

c) rad 3/2

Step-by-step explanation:

If Cos 30° equals rad 3/2 then the sin 60° equals rad 3/2.

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2 years ago

Tina has been dieting for a total fo 13 weeks. She lost 3 pounds on the first week of her diet, but gained back a pound on the s

PIT_PIT [208]

Answer:

4 she lost 4 pounds, how do u not know this dood

Step-by-step explanation:

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2 years ago

Which of the following equations is equivalent to −6x+2y=24?

s344n2d4d5 [400]

Answer:

The choice three ;

$y = 3x + 12$

Step-by-step explanation:

$- 6x + 2y = 24 \\ 2y = 24 + 6x \\ \\ y = \frac{24 + 6x}{2} \\ \\ y = \frac{24}{2} + \frac{6x}{2} \\ \\ y = 12 + 3x$

3 0

1 year ago

Can anyone help me with this Midterm Advanced Algebra problem. (DONT ANSWER IF YOUR NOT SURE)

tigry1 [53]

Answer:

y = -1/2x + 13/2

Step-by-step explanation:

The slope of a line that is perpendicular to a line will be a negative reciprocal. When you rewrite 2x-7=8 into slope-intercept form, you get y=2x-8. The negative reciprocal of the slope 2x is -1/2x. There is only one option with this slope. If you're still not sure then you can use a graphing calculator to check this. An online one would be desmos

3 0

2 years ago

Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and

Anastaziya [24]

The problem is modelled in the first picture shown below

To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector.

We use the cosine rule to work out the length AB
$AB^{2}= 75^{2}+ 150^{2}-(2*75*150*cos(60))$
$AB^{2} =28125-11250$
$AB^{2}=16875$
$AB= \sqrt{16875} =130$ (nearest whole number)

The third picture shows the full diagram of the vectors

To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B

Angle A
$\frac{130}{sin(60)}= \frac{75}{sin(A)}$
$130sin(A)=75sin(60)$
$sin(A)= \frac{75sin(60)}{130}$
$sin(A)=0.4996300406$
$A= sin^{-1}(0.4996300406)$
$A=30$ (rounded to nearest whole number)

Angle B
$B=180-60-30=90$

Direction is 60° toward negative x-axis

Answer: Magnitude 130N and direction 60° toward negative x-axis

3 0

2 years ago