Find the probability that a randomly selected light bulb will last between 750 and 825 hours.
1 answer:
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(_/18+2_/3)^(2
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
Answer:
B=
Step-by-step explanation:
Let's do the multiplication AB.
If A=
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!