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Neporo4naja [7]
3 years ago
10

f(x)=5xf(x)=5x and g(x)=x−3g(x)=x−3 Step 1 of 2 : Find the formula for (f+g)(x)(f+g)(x) and simplify your answer. Then find the

domain for (f+g)(x)(f+g)(x). Round your answer to two decimal places, if necessary.
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

(f+g)(x)=6x-3

domain is (-∞,∞)

Step-by-step explanation:

f(x)=5x

g(x)=x-3

(f+g)(x)=f(x)+g(x)

to find f+g(x) we add both function

Substitute f(x) and g(x)

(f+g)(x)=f(x)+g(x)

(f+g)(x)=5x+x-3=6x-3

(f+g)(x)=6x-3

Domain is the set of x values

here there is no restriction for x

so domain is the set of all real numbers

domain is (-∞,∞)

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How do you write 22.5% as a fraction in simplest form?
Darya [45]

Answer: 9/40

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So here, 22.5% can be written as the ratio 22.5 to 100 or 22.5/100.

Notice however that 22.5/100 is not in lowest terms so we need to multiply the numerator and the denominator of 22.5 by 10 in order to remove the decimal point. When we do this, we will end up with the fraction 225/1000.

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Therefore, 22.5% can be written as the fraction 9/40.

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From a group of 13 women and ​12 men, a researcher wants to randomly select 8 women and 8 men for a study. In how many ways can
Fantom [35]

The total number of ways the study can be selected is: 637065

Given,

Total number of women in a group= 13

Total number of men in a group = 12

Number of women chosen = 8

Number of men chosen = 8

∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.

This in the form of combination factor = nCr

                                                     ∴ nCr = n!/(n₋r)! r!

13C₈ = 13!/(13 ₋ 8)! 8!

        = 13!/5!.8!

        = 1287

12C₈ = 12!/(12₋8)! 8!

        = 12!/5! 8!

        = 495

Now multiply both the combinations of men and women

= 1287 × 495

= 637065

Hence the total number of ways the study group is selected is 637065

Learn more about "Permutations and Combinations" here-

brainly.com/question/11732255

#SPJ10

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