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inna [77]
3 years ago
10

True of false: 1+1 has the same answer as 1x1

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0
False, 1+1=2, 1x1=1……
Goshia [24]3 years ago
4 0

Answer:

False

Step-by-step explanation:

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PLEASE HELP!! I NEED THIS TO PASS.
Tanzania [10]
Let's apply the Law of Cosines here.  We want the measure of the angle opposite the side with length 16.

Call that angle C.

Then 16^2 = 36^2 + 28^2 - 2(36)(28)cos C.

Solving for C:  cos C = 16^2 - 36^2 - 28^2 
                                     -------------------------  = 0.904, and C = 0.44 rad
                                         -2(28)(36)                           or  C = 25.21 degrees

So each of the 2 equal angles shown has the measure 25.21 degrees.

Unfortunately, I don't know the direction we should go from this point on.




3 0
3 years ago
What is the combined height of 3 nickels, 2 nickels and 1 nickels
Oduvanchick [21]
I assume it would be a combined height of 6 nickles.
8 0
3 years ago
Read 2 more answers
Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert
Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

                        s=ut+\frac{1}{2} at^{2}

Here, s = distance of the balloon above the ground = - 80 feet

          u = intital velocity = 16 feet per second

          a = acceleration of the object = -32 feet per second

          t = required time

So,  s=ut+\frac{1}{2} at^{2}

      -80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})

       -80=16t-16 t^{2}

       16 t^{2} -16t -80 =0

          t^{2} -t -5 =0

Now, we will use the quadratic D formula for finding the value of t, i.e;

           t = \frac{-b\pm \sqrt{D } }{2a}

Here, a = 1, b = -1, and c = -5

Also, D = b^{2} -4ac = (-1)^{2} -(4 \times 1 \times -5) = 21

So,  t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}

      t = \frac{1\pm \sqrt{21 } }{2}

We will neglect the negative value of t as time can't be negative, so;

t = \frac{1+ \sqrt{21 } }{2} = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

                       v=u+at

Here, v = final velocity

So,  v=16+(-32 \times 2.79)

      v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

8 0
3 years ago
How is the equation on the top equivalent to 3. Show 5 steps on how you did it.
Sloan [31]

(9)^4 × (27)^3 × (81)^2 / (3)^24 = 3.

Explanation:

  • All the numbers in the numerator i.e. 9, 27, 81 are multiples of 3.
  • 9 = 3 × 3 = 3², 27 = 3 × 3 × 3 = 3³, 81 = 3 × 3 × 3 × 3 = 3^{4}.
  • 9^{4} = (3^2)^4, 27³ = (3^3)^3, 81^2 = (3^4)^2.
  • According to the power rule, (a^x)^y = a^xy.
  • So the given numbers can be written as follows                                                         9^{4} = 3^8, 27³ = 3^9 and 81² = 3^8.
  • According to the product rule, (a^x) × (a^y) = a^xy.
  • So the numerator can be written as                                                                             9^{4} × 27³ × 81² = (3^8) × (3^9) × (3^8) = 3^(8+9+8) = 3^25.
  • So the fraction becomes 3^25 / 3^24 = 3 × 3^24 / 3^24 = 3.

4 0
3 years ago
Find the value of:<br><img src="https://tex.z-dn.net/?f=%2027x%5E%7B3%7D%2B8%20y%5E%7B3%7D%20%20" id="TexFormula1" title=" 27x^{
kirill [66]
27x^3+8y^3=(3x)^3+(2y)^3=(3x+2y)[(3x)^2-3x\cdot2y+(2y)^2]\\\\=(3x+2y)[(3x)^2+2\cdot3x\cdot2y+(2y)^2-3\cdot3x\cdot2y]\\\\=(3x+2y)[(3x+2y)^2-18xy]=(*)\\---------------------------\\3x+2y=20\\\\xy=\frac{14}{9}\\------------------------------\\(*)=20\cdot(20^2-19\cdot\frac{14}{9})=20\cdot(400-18\cdot\frac{14}{9})=20\cdot(400-2\cdot14)\\\\=20\cdot(400-28)=20\cdot372=7440



a^3+b^3=(a+b)(a^2-ab+b^2)\\\\(a+b)^2=a^2+2ab+b^2
5 0
3 years ago
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