Answer:
The beat frequency is 0.0019 MHz.
Explanation:
Given that,
Velocity = 0.32 m/s
Frequency = 4.40 MHz
Speed of wave = 1540 m/s
We need to calculate the frequency
Case (I),
Observer is moving away from the source
Using Doppler's effect
![f'=\dfrac{v-v'}{v}f](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7Bv-v%27%7D%7Bv%7Df)
Where, v' = speed of observer
Put the value into the formula
![f'=\dfrac{1540-0.32}{1540}\times4.40](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7B1540-0.32%7D%7B1540%7D%5Ctimes4.40)
![f'=4.399\ MHz](https://tex.z-dn.net/?f=f%27%3D4.399%5C%20MHz)
Case (II),
Cell is as the source of sound of frequency f' and it moving away from the observer.
Using formula of frequency
![f''=\dfrac{v-v_{s}}{v+v_{s}}\times f](https://tex.z-dn.net/?f=f%27%27%3D%5Cdfrac%7Bv-v_%7Bs%7D%7D%7Bv%2Bv_%7Bs%7D%7D%5Ctimes%20f)
![f''=\dfrac{1540-0.32}{1540+0.32}\times4.399](https://tex.z-dn.net/?f=f%27%27%3D%5Cdfrac%7B1540-0.32%7D%7B1540%2B0.32%7D%5Ctimes4.399)
![f''=4.3971\ MHz](https://tex.z-dn.net/?f=f%27%27%3D4.3971%5C%20MHz)
We need to calculate the beat frequency
![\Delta f= f'-f''](https://tex.z-dn.net/?f=%5CDelta%20f%3D%20f%27-f%27%27)
![\Delta f=4.399-4.3971=0.0019\ MHz](https://tex.z-dn.net/?f=%5CDelta%20f%3D4.399-4.3971%3D0.0019%5C%20MHz)
Hence, The beat frequency is 0.0019 MHz.
Answer:
but I can tomorrow if you have time can you come to the meeting tonight but yyyy the person who is this and what
Explanation:
gyyyyyyyyyyyyyyyyy the number of the person who is this and what is the
Answer:
See explanation for details
Explanation:
The full mechanism of the nitration of an aromatic ring (benzene) is shown in the image attached. The electrophile is NO2^+. It us generated from HNO3/H2SO4. it attacks the benzene ring and leads to the formation of a delocalized intermediate which rearranges to form the product, in this case, nitrobenzene. Note that the intermediate can also be represented by a number of resonance structures.
The heat transferred by conduction per hour if temperature difference between the inner body and the skin is ∆ = 2°C is 18 Joule/ hr.
<h3>What is heat conduction?</h3>
Heat conduction is the method of transfer of heat by the direct contact of the two or more solid bodies.
Given is the thickness of tissue x = 3cm =-0.03m, Area of conduction A = 1.5 m², Change in temperature of skin ΔT =2°C, and coefficient of thermal for tissue without blood is k = 18 × 10⁻² Cal /m-hr- °C
The conduction heat rate in hr is
Q =kAΔT /x
Q =18 × 10⁻² x 1.5 x 2 /0.03
Q =18 Joule / hr
Thus, the heat transferred by conduction per hour, if temperature difference between the inner body and the skin is ∆ = 2°C is 18 Joule/ hr.
Learn more about conduction.
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