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Shkiper50 [21]
4 years ago
10

Do you think climate change is affecting our seasons? Why or why not? Share the links you found that support your theory.

Physics
1 answer:
mestny [16]4 years ago
6 0

Answer:

Yes, it is. The summers and the winters are getting warmer. Also in cold places like Alaska, the temperatures are rising.

Explanation:

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The following statement is FALSE. You must replace the capitiized word with a different word that will make this statement corre
DiKsa [7]
The answer could be transfer
4 0
3 years ago
The block on this incline weighs 100 kg and is connected by a cable and pulley to a weight of 10 kg. If the coefficient of frict
blondinia [14]

Answer:

a. 94.54 N

b. 0.356 m/s^2

Explanation:

Given:-

- The mass of the inclined block, M = 100 kg

- The mass of the vertically hanging block, m = 10 kg

- The angle of inclination, θ = 20°

- The coefficient of friction of inclined surface, u = 0.3

Find:-

a) The magnitude of tension in the cable

b) The acceleration of the system

Solution:-

- We will first draw a free body diagram for both the blocks. The vertically hanging block of mass m = 10 kg tends to move "upward" when the system is released.

- The block experiences a tension force ( T ) in the upward direction due the attached cable. The tension in the cable is combated with the weight of the vertically hanging block.

- We will employ the use of Newton's second law of motion to express the dynamics of the vertically hanging block as follows:

                        T - m*g = m*a\\\\  ... Eq 1

Where,

              a: The acceleration of the system

- Similarly, we will construct a free body diagram for the inclined block of mass M = 100 kg. The Tension ( T ) pulls onto the block; however, the weight of the block is greater and tends down the slope.

- As the block moves down the slope it experiences frictional force ( F ) that acts up the slope due to the contact force ( N ) between the block and the plane.

- We will employ the static equilibrium of the inclined block in the normal direction and we have:

                        N - M*g*cos ( Q )= 0\\\\N = M*g*cos ( Q )

- The frictional force ( F ) is proportional to the contact force ( N ) as follows:

                        F = u*N\\\\F = u*M*g *cos ( Q )

- Now we will apply the Newton's second law of motion parallel to the plane as follows:

                       M*g*sin(Q) - T - F = M*a\\\\M*g*sin(Q) - T -u*M*g*cos(Q)  = M*a\\ .. Eq2

- Add the two equation, Eq 1 and Eq 2:

                      M*g*sin ( Q ) - u*M*g*cos ( Q ) - m*g = a* ( M + m )\\\\a = \frac{M*g*sin ( Q ) - u*M*g*cos ( Q ) - m*g}{M + m} \\\\a = \frac{100*9.81*sin ( 20 ) - 0.3*100*9.81*cos ( 20 ) - 10*9.81}{100 + 10}\\\\a = \frac{-39.12977}{110} = -0.35572 \frac{m}{s^2}

- The inclined block moves up ( the acceleration is in the opposite direction than assumed ).

- Using equation 1, we determine the tension ( T ) in the cable as follows:

                     T = m* ( a + g )\\\\T = 10*( -0.35572 + 9.81 )\\\\T = 94.54 N

4 0
3 years ago
Ben and Jerry, arch rivals, decide to have a weight lifting contest during PE. Ready, set, go! Ben and Jerry both lift a 250 kg
Sidana [21]

The answer is B. Your welcome.

B    ) STILL CHILL

7 0
3 years ago
Read 2 more answers
A hill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. At
GaryK [48]

Answer:

angle is 19.85°

Explanation:

given data

grade = 36.1 %

vertically distance y = 36.1 m

horizontal distance x = 100 m

to find out

angle

solution

we know that according to question here

it make a triangle shape that contain 100 m base and height 36.1 m

and make angle with base is θ

so by triangle we know here

tanθ = y/x   ..........1

so we now put x and y and find θ

tanθ = 36.1 / 100

tanθ = 0.361

θ = 19.85°

so angle is 19.85°

7 0
3 years ago
Which of the following statements about transition metals is true?
Levart [38]
It would probably be C
7 0
3 years ago
Read 2 more answers
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