I’m sorry i don’t know the answer
Answer:
the speed of the block at the given position is 21.33 m/s.
Explanation:
Given;
spring constant, k = 3500 N/m
mass of the block, m = 4 kg
extension of the spring, x = 0.2 m
initial velocity of the block, u = 0
displacement of the block, d =1.3 m
The force applied to the block by the spring is calculated as;
F = ma = kx
where;
a is the acceleration of the block

The final velocity of the block at 1.3 m is calculated as;
v² = u² + 2ad
v² = 0 + 2ad
v² = 2ad
v = √2ad
v = √(2 x 175 x 1.3)
v = 21.33 m/s
Therefore, the speed of the block at the given position is 21.33 m/s.
Answer:
The average speed of the bear is 5.3 km/h.
Explanation:
Hi there!
The average <u>speed</u> is calculated as the distance traveled divided by the time in which that distance was covered. The bear traveled 4 km (1 km south, 1 km east, 1 km north and 1 km west) in 45 min. It does not matter the direction at which the bear traveled, only how much distance the bear moved. So the average speed (a.s) will be:
a.s = d/t
Where:
d = traveled distance.
t = time in which that distance was covered.

The average speed of the bear is 5.3 km/h.
Notice that if the question would have asked to find the average <u>velocity,</u> the answer would have been zero because the total displacement of the bear was zero (it returned to the initial point). The average velocity is calculated as the displacement over time.
Answer:
Explanation:(3.9x100)(4.1x10,000)
390x41,000
15,990,000
Answer:

Explanation:
We must use conservation of linear momentum before and after the collision, 
Before the collision we have:

where these are the masses are initial velocities of both players.
After the collision we have:

since they clong together, acting as one body.
This means we have:

Or:

Which for our values is:
