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Kipish [7]
2 years ago
8

Describe the shape of the earth besides round and tell me how it rotates​

Physics
1 answer:
NNADVOKAT [17]2 years ago
8 0

Answer:

The Earth is in hydrostatic equilibrium pretty much. Which is to say that if it were entirely liquid it would still be the same shape ignoring minor differences like mountain ranges that are in any case indistinguishable on the large scale.

A spinning liquid sphere will flatten out somewhat at the axis poles and expand somewhat in its equatorial region and that’s the way the Earth is.

Hope it wirks

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Please answer fast ————-
Citrus2011 [14]
I’m sorry i don’t know the answer
4 0
3 years ago
A spring whose stiffness is 3500 N/m is used to launch a 4 kg block straight up in the classroom. The spring is initially compre
jarptica [38.1K]

Answer:

the speed of the block at the given position is 21.33 m/s.

Explanation:

Given;

spring constant, k = 3500 N/m

mass of the block, m = 4 kg

extension of the spring, x = 0.2 m

initial velocity of the block, u = 0

displacement of the block, d =1.3 m

The force applied to the block by the spring is calculated as;

F = ma = kx

where;

a is the acceleration of the block

a = \frac{kx}{m} \\\\a = \frac{(3500) \times (0.2)}{4} \\\\a = 175 \ m/s^2

The final velocity of the block at 1.3 m is calculated as;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2ad

v = √2ad

v = √(2 x 175 x 1.3)

v = 21.33 m/s

Therefore, the speed of the block at the given position is 21.33 m/s.

5 0
3 years ago
A polar bear starts at the North Pole. It travels 1.0 km south, then 1.0 km east, then 1.0 km north, then 1.0 km west to return
stiks02 [169]

Answer:

The average speed of the bear is 5.3 km/h.

Explanation:

Hi there!

The average <u>speed</u> is calculated as the distance traveled divided by the time in which that distance was covered. The bear traveled 4 km (1 km south, 1 km east, 1 km north and 1 km west) in 45 min. It does not matter the direction at which the bear traveled, only how much distance the bear moved. So the average speed (a.s) will be:

a.s = d/t

Where:

d = traveled distance.

t = time in which that distance was covered.

a.s = \frac{4 km}{45 min(\frac{1 h}{60 min}) } = 5.3\frac{km}{h}

The average speed of the bear is 5.3 km/h.

Notice that if the question would have asked to find the average <u>velocity,</u> the answer would have been zero because the total displacement of the bear was zero (it returned to the initial point). The average velocity is calculated as the displacement over time.

3 0
4 years ago
What do (3.9 x 10^2)(4.1 x 10^4) equal
pantera1 [17]

Answer:

Explanation:(3.9x100)(4.1x10,000)                

390x41,000

15,990,000

8 0
3 years ago
Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i
romanna [79]

Answer:

v_f=0.825m/s

Explanation:

We must use conservation of linear momentum before and after the collision, p_i=p_f

Before the collision we have:

p_i=p_1+p_2=m_1v_1+m_2v_2

where these are the masses are initial velocities of both players.

After the collision we have:

p_f=(m_1+m_2)v_f

since they clong together, acting as one body.

This means we have:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Or:

v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Which for our values is:

v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s

7 0
4 years ago
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