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muminat
3 years ago
12

Which of the following equations represents the axis of symmetry for the parabola shown? (5 points)

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0
Which of the following equations represents the axis of symmetry for the parabola shown? (5 points)y = 10x
x = 10
x = y + 10
y = x + 10
The following equations that best represents the axis of symmetry for the parabola shown is x = 10. 
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Simplify the following expression.
HACTEHA [7]
Remember that exponentioal rule
x^m times x^n=x^(m+n)
therefor
7^4 times 7^-6=7^(4-6)=7^(-2)
remember the other rule
x^-m=1/(x^m) so
7^-2=1/(7^2)=1/49
answe ris A
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3 years ago
Solve: m + 2/3 = 1/2<br> A. 1 1/6<br> B. 1/6<br> C. -1<br> D-1/6
xxMikexx [17]

I think the answer is (D).

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Which of the following are line segments shown in the drawing?​
vesna_86 [32]

Answer:

BE

Step-by-step explanation:

This is because it is the part of a line that has two endpoints and is finite in length.

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1 year ago
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Suppose there is a 1.2°F drop in temperature for every thousand feet that an airplane climbs into the sky. If the temperature on
Nesterboy [21]

Answer: 49.7^{\circ}F

Step-by-step explanation:

Given

The temperature on the ground is 56.9^{\circ}F

temperature drop observed is 1.2^{\circ}F\ \text{per 1000 ft}

The height of the plane is  6000\ ft

The total increase in height per 1000\ ft is 6 units

Temperature drop is

\Rightarrow 1.2\times 6=7.2^{\circ}F

The temperature at that altitude is

\Rightarrow 56.9-7.2=49.7^{\circ}F

5 0
3 years ago
Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1
Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

8 0
2 years ago
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