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inn [45]
2 years ago
14

Can someone tell me I’m correct or correct me please that would be lovely

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
7 0

Answer:

correct brosefina. have a day

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The first ferris wheel was 250 feet in diameter. It was invented by John Ferris in 1893. Assuming it made one revolution every 3
victus00 [196]

Step-by-step explanation:

The wheel has a diameter of 250 feet, so its circumference is:

C = 2πr = πD

C = 250π feet

It makes one revolution in 30 seconds, or half a minute, so the linear speed of the passenger is:

v = d / t

v = 250π / 0.5

v = 500π ft/min

v ≈ 1571 ft/min

This is about the same as 17.9 mph.

6 0
3 years ago
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5
mixer [17]
The answer to your question Meowgatita15, is D. 
6 0
3 years ago
Please answer this correctly
Illusion [34]

Answer:

$15.50

Step-by-step explanation:

0.5 (1) + 5 (3)

0.5 + 15

15.50

7 0
3 years ago
Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
What is the answer to the question " 6(5x(41-36)-(8+14))
alisha [4.7K]
So  41-36=5, 5x5=25, which makes it 6(25-(8+14)). So then it's 6(25-22), which is 6x3, which is 18. (So 18 is the answer). 
5 0
3 years ago
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