The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

$n_i=8$

$\lambda=3745\ nm$

The amount of energy change during the transition is given by :

$\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]$

And

$\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]$

Plugging all the values we get :

$\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5$

So, the final level of the electron is 5.

4 0

2 years ago

Which scenario would result in a population growth of zero? Use this formula: population growth = (birth rate + immigration) – (

swat32

Answer:

12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born

Explanation:

From the formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

= (b + i) - (d + e)

For the first option, b = 12, i = 0, d = 12, e = 12

population growth = (12+0) - (12+12) = -12

For the second option: b = 13, i = 0, d = 3, e = 16

population growth = (13+0) - (3+16) = -6

For the third option: b = 12, i = 20, d = 0, e = 8

population growth = (12+20) - (0+8) = 24

For the last option: b = 0, i = 14, d = 4, e = 10

population growth = (0+14) - (4+10) = 0

Hence, the last option is the correct option.

8 0

2 years ago

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Can you guys help me with 8&9 THANK YOUU

zlopas [31]

number 8 the list is hydrogen,magnesium,silicon and oxygen and there are 4elements

8 0

2 years ago

WILL GIVE BRAINLIEST!! :)

svetlana [45]

Answer:

Explanation:

Nitrogen is a naturally occurring element that is essential for growth and reproduction in both plants and animals. It is found in amino acids that make up proteins, in nucleic acids, that comprise the hereditary material and life's blueprint for all cells, and in many other organic and inorganic compounds.

5 0

2 years ago

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