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e-lub [12.9K]
2 years ago
6

Please help me balance this equation!!!! _KOH + _HBr → -KBr + _H2O

Chemistry
2 answers:
Naddika [18.5K]2 years ago
8 0

Answer: KOH + HBr = H2O + KBr

Explanation: hope this helps

mart [117]2 years ago
6 0

I think it's already balanced so just put a 1 on all of them .

K - 1, 1

O - 1, 1

H - 2, 2

Br - 1, 1

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2 years ago
0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (
SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

Molarity = \frac{moles}{volume(in L)}\\= \frac{0.5 moles}{2.00 L}\\= 0.25 M

Thus, we can conclude that molarity of this solution is 0.25 M.

4 0
2 years ago
3. Which type of rock is formed 20 kilometers below Earth's surface? (1 sedimentary 2. metamorphic 3. igneous 4.magma please hel
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8 0
3 years ago
Read 2 more answers
How many grams of water can be produced from 4.6 grams of Hydrogen and 7.3 grams of Oxygen?
12345 [234]

Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

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Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

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From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

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                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

                          x = 8.21 g of H₂O

4 0
3 years ago
Why is the? The second ionization energy of sodium is about three times greater than the second ionization energy of magnesium
Scorpion4ik [409]

Answer:

~Na+1 is already in the preferred form. Because of this, the second ionization energy of sodium is higher than normal. Mg+1 loses an electron to form s2 p6 .

3 0
2 years ago
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