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2 years ago

This isn't urgent but I need help and I will give Brainliest Promise!

Mathematics

2 answers:

zvonat [6]2 years ago

5 0

Answer:

1/3

Step-by-step explanation:

nirvana33 [79]2 years ago

3 0

rate of change as in the gradient??
if yes then the formula would be rise over run, so y over x, therefore 1/3

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Elias has decided to fence in a garden that is in the shape of a parallelogram. If one side measures 76 ft and 250 ft of fencing

Leni [432]

The length of side of garden are 76 feet and 49 feet

Solution:

Given that, Elias has decided to fence in a garden that is in the shape of a parallelogram

Measure of one side = 76 feet

250 ft of fencing is needed to enclose the garden

Therefore, perimeter = 250

The perimeter of parallelogram is given by:

Perimeter = 2(a + b)

Where, a and b are the length of sides

Here, a = 76

b = ?

Substituting in formula, we get

250 = 2(76 + b)

250 = 152 + b

2b = 250 - 152

2b = 98

b = 49

Thus the length of side of garden is 49 feet

8 0

2 years ago

write in graphing form please! A parabola that opens down with no stretch factor that has a vertex of (-6,5)

wolverine [178]

If it has no stretch factor, then there will be no coefficient. Meaning this is a lot easier. So, we equation is

(x+6)^2 + 5

Hope this helps!

8 0

2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago

Solve 2(b − 3) ≥ 3(3 − b) and describe the graph of the solution. Show all your work.

solong [7]

Answer:

$\large\boxed{b\geq3\to b\in[3,\ \infty)}$

Step-by-step explanation:

$2(b-3)\geq3(3-b)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\(2)(b)+(2)(-3)\geq(3)(3)+(3)(-b)\\\\2b-6\geq9-3b\qquad\text{add 6 to both sides}\\\\2b-6+6\geq9+6-3b\\\\2b\geq15-3b\qquad\text{add}\ 3b\ \text{to both sides}\\\\2b+3b\geq15-3b+3b\\\\5b\geq15\qquad\text{divide both sides by 5}\\\\\dfrac{5b}{5}\geq\dfrac{15}{5}\\\\b\geq3$

$,\ \geq-\text{line to the right}\\-\text{o}\text{pen circle}\\\leq,\ \geq-\text{closed circle}$

4 0

3 years ago

Tim has twice as many marbles as Luke together they have 39 marbles how many marbles does time have

Travka [436]

Tim has 2 times as luke
t=2l
they have 29 goether
t+l=39
subsitute
2l+l=39
3l=39
divide by 3
l=13

subsitue
t=2l
t=2(13)
t=26

tim has 26 and luke has 13
I don't know how many marble Tim has but probably all of them since alll must die and then the marbles go to Time

3 0

3 years ago

Read 2 more answers