Because <span> The half-life of carbon-14 is around 5,700 years. So, by measuring the half-live of the sample, we could predict how old the sample actually is.
</span><span>After 50,000 years there is probably less than 1% of the original C-14 left which make it much more accurate to measure, so, the upward limit is put on 50,000 years.</span>
Both of them are a hope this helps
Answer:
Explanation:
The relation between equilibrium constant and Ecell is given below .
E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K
E⁰cell = 1.46 - 1.21 = .25 V
n = 2
Putting the values
.25 = (8.314 x 298 lnK) / (2 x 96485 )
lnK = 19.47
K = 2.85 x 10⁸
2 )
Change in free energy Δ G
Δ G ⁰ = nE⁰ F
n = 4
E⁰ = .4 + .83 = 1.23 V
Δ G ⁰= 4 x 1.23 x 96485
= 474706 J / mol
3 )
E⁰cell = (RT / nF ) lnK
n = 2
1.78 = 8.314 x 298 lnK / 2 x 96485
lnK = 138.638
K = 1.62 x 10⁶⁰
List of the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) is below,
Here , we have to list the metals that form only one type of ion (that is, metals whose charge is invariant from one compound to another) and have to identify the group numbers of these metals.
- Hydrogen H+
- Lithium Li+
- Sodium Na+
- Potassium K+
- Rubidium Rb+
- Cesium Cs+
- Beryllium Be2+
- Magnesium Mg2+
- Calcium Ca2+
- Strontium Sr2+
- Barium Ba2+
- Aluminum Al3+
- Zinc Zn2+
- Scandium Sc3+
- Silver Ag+
Co is stable in both +2 and +3 oxidation state. So it can variable. Li only have +1 charge. So it is invariable from one compound to other.
To learn more about metals, here
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Fertilizer use the run on can go into fresh water
